
Bihar Board Class 12 Physics Set A Question Paper 2026 with Solution pdf is available here for download. The exam was conducted by the Bihar School Examination Board on 3rd Feb 2026 in the first shift for a duration of 3 hours 15 min. Bihar Board Class 12 Physics exam is total of 70 Marks.
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Section A
The nuclear density is approximately
Nuclear density (\(\rho\)) is defined as the ratio of nuclear mass to nuclear volume.
Nuclear Mass \(M \propto A\) (Mass Number).
Nuclear Volume \(V = \frac{4}{3}\pi R^3 = \frac{4}{3}\pi (R_0 A^{1/3})^3 \propto A\).
Therefore, \(\rho = \frac{M}{V} \propto \frac{A}{A} = constant\).
It is approximately \(2.3 \times 10^{17} \, kg/m^3\) for all nuclei.
Quick Tip: This incredibly high density implies that the nucleus is extremely compact.
In a transistor
A transistor has three regions: Emitter, Base, and Collector.
Doping levels are: Emitter \(>\) Collector \(>\) Base.
The Emitter is heavily doped to supply carriers.
The Base is lightly doped (minimum impurity) and very thin to reduce recombination.
The Collector is moderately doped.
Quick Tip: Order of Doping: Emitter \(>\) Collector \(>\) Base. Order of Size: Collector \(>\) Emitter \(>\) Base.
Coulomb's law is valid for
Coulomb's law states that the force between two point charges is directly proportional to the product of charges and inversely proportional to the square of the distance between them.
It is strictly applicable only to stationary point charges.
For distributed or dispersed charges, integration methods (calculus) based on Coulomb's law are used, but the law itself is defined for points.
Quick Tip: If spheres are charged, they behave as point charges concentrated at their centers only if they are uniformly charged and seen from outside.
S.I. unit of electric flux is
Electric Flux \(\phi_E = \vec{E} \cdot \vec{A}\).
The unit of Electric Field \(E\) is Volt/meter (\(V/m\)) or Newton/Coulomb (\(N/C\)).
The unit of Area \(A\) is square meter (\(m^2\)).
So, unit of \(\phi_E = (V/m) \times m^2 = Vm\) (Volt-meter).
Alternative unit: \((N/C) \times m^2 = N m^2 C^{-1}\).
Quick Tip: Do not confuse with Magnetic Flux, which is measured in Weber (Wb) or Tm\(^2\).
A cell of internal resistance r is connected to an external resistance R. The current will be maximum in R, if
(Note: While maximum current strictly flows when \(R=0\), this question refers to the Maximum Power Transfer Theorem, which is a standard board exam question format often phrased this way).
Current in the circuit is \(I = \frac{E{R+r}\).
Power delivered to the external resistance is \(P = I^2 R = \left(\frac{E}{R+r}\right)^2 R\).
For maximum power transfer, the external resistance must equal the internal resistance (\(R = r\)).
Given the options, \(R=r\) is the intended answer corresponding to the critical condition for maximum output (power).
Quick Tip: Maximum Power Transfer Theorem: Output power is maximum when Load Resistance = Internal Resistance.
If L and R represent inductance and resistance respectively, then the unit of L/R will be
The quantity \(L/R\) is known as the Time Constant (\(\tau\)) of an RL circuit.
It represents the time taken for the current to reach approximately 63% of its maximum value.
Therefore, its unit is the unit of time, which is the Second.
Dimensional verification: \(L = [ML^2T^{-2}A^{-2}]\), \(R = [ML^2T^{-3}A^{-2}]\). \(L/R = [T]\).
Quick Tip: Similarly, for an RC circuit, the time constant is \(RC\), which also has the unit of seconds.
In a metallic conductor, the current is carried by
In metallic conductors, the atoms form a lattice where the nuclei and inner electrons are fixed.
The valence electrons are loosely bound and become "free electrons" that can move throughout the lattice.
These free electrons are the charge carriers responsible for electric current in metals.
Protons are bound in the nucleus and do not move.
Quick Tip: In electrolytes, both positive and negative ions act as charge carriers.
The dimensions of \(\frac{B_0^2}{\mu_0}\) will be the same as that of
The energy stored per unit volume in a magnetic field (Magnetic Energy Density) is given by the formula \(u_B = \frac{B^2}{2\mu_0}\).
Therefore, the quantity \(\frac{B_0^2}{\mu_0}\) has the same dimensions as Energy Density.
Energy Density = \(\frac{Energy}{Volume} = \frac{ML^2T^{-2}}{L^3} = [ML^{-1}T^{-2}]\).
Quick Tip: This is analogous to Electric Energy Density: \(u_E = \frac{1}{2}\epsilon_0 E^2\).
Nickel is
Ferromagnetic materials are those which are strongly attracted by magnetic fields.
The most common examples of ferromagnetic materials are Iron (Fe), Cobalt (Co), and Nickel (Ni).
Therefore, Nickel is ferromagnetic.
Quick Tip: Above the Curie temperature, ferromagnetic substances become paramagnetic.
In a half-wave rectifier, if the input frequency is 50 Hz, then output frequency will be
A half-wave rectifier passes only one half-cycle of the AC input.
This produces one pulse of output for every one full cycle of input.
Therefore, the period of the output wave is the same as the input wave.
Consequently, the output frequency is equal to the input frequency (50 Hz).
Quick Tip: For a Full-Wave Rectifier, the output frequency is \textbf{double} the input frequency (100 Hz in this case).
How many joules of energy will be released due to mass defect of 1 mg?
Using Einstein's mass-energy equivalence relation: \(E = mc^2\).
Given Mass \(m = 1 mg = 1 \times 10^{-3} g = 1 \times 10^{-6} kg\).
Speed of light \(c = 3 \times 10^8 m/s\).
\(E = (10^{-6}) \times (3 \times 10^8)^2\).
\(E = 10^{-6} \times 9 \times 10^{16} = 9 \times 10^{10} J\).
Quick Tip: Always convert mass to kg (SI unit) before calculating energy in Joules.
The ratio of de Broglie wavelength associated with two electrons accelerated through 49 V and 64 V is
The de Broglie wavelength of an electron accelerated through potential \(V\) is given by \(\lambda = \frac{12.27}{\sqrt{V}} \AA\).
So, \(\lambda \propto \frac{1}{\sqrt{V}}\).
\(\frac{\lambda_1}{\lambda_2} = \sqrt{\frac{V_2}{V_1}}\).
Given \(V_1 = 49\) V and \(V_2 = 64\) V.
\(\frac{\lambda_1}{\lambda_2} = \sqrt{\frac{64}{49}} = \frac{8}{7}\).
Quick Tip: Remember the inverse square root relationship: Higher voltage \(\rightarrow\) Higher momentum \(\rightarrow\) Shorter wavelength.
A ray of light is incident normally on a plane mirror. The angle of reflection will be
When a ray falls normally (perpendicularly) on a mirror, it travels along the normal.
The angle of incidence (\(i\)) is the angle between the incident ray and the normal. Here, \(i = 0^\circ\).
According to the law of reflection, Angle of Incidence (\(i\)) = Angle of Reflection (\(r\)).
Therefore, \(r = 0^\circ\). The ray retraces its path.
Quick Tip: Don't confuse angle with the surface (\(90^\circ\)) with angle of incidence (\(0^\circ\)).
The phase difference \(\phi\) is related to path difference \(\lambda\) by
(Note: The question uses the symbol \(\lambda\) incorrectly for path difference variable \(\Delta x\). The standard formula connects \(\phi\) and path difference).
The relationship between Phase Difference (\(\phi\)) and Path Difference (\(\Delta x\)) is:
\(\phi = \frac{2\pi}{\lambda} \times \Delta x\)
Rearranging for Path Difference (\(\Delta x\)):
\(\Delta x = \frac{\lambda}{2\pi} \times \phi\)
The question asks for the expression equal to the path difference (denoted confusingly as \(\lambda\) in Hindi text or just asking for relation). Option (C) matches this form.
Quick Tip: A path difference of one full wavelength (\(\lambda\)) corresponds to a phase difference of \(2\pi\) radians.
Who first explained electromagnetic waves mathematically?
James Clerk Maxwell unified electricity and magnetism into a single theory.
He formulated a set of equations (Maxwell's Equations) which mathematically predicted the existence of electromagnetic waves.
Heinrich Hertz later proved their existence experimentally.
Quick Tip: Maxwell showed that light is an electromagnetic wave.
Which factor of the following does not affect resistance of a conducting wire?
The resistance (\(R\)) of a conductor is given by \(R = \rho \frac{L}{A}\).
It depends on:
1. Length (\(L\)).
2. Cross-sectional Area (geometry).
3. Material (Resistivity \(\rho\)).
4. Temperature (affects \(\rho\)).
It is a property of the conductor itself and does not depend on the applied Voltage (\(V\)) or Current (\(I\)), although \(V=IR\) defines the relationship between them.
Quick Tip: Ohm's law states \(V/I\) is constant (\(R\)), implying \(R\) is independent of V.
When a dielectric is placed in an external electric field, the effective electric field inside the dielectric
When a dielectric is placed in an electric field \(E_0\), the molecules get polarized.
This polarization induces an internal electric field \(E_p\) in the opposite direction to the external field.
The net electric field inside is \(E_{net} = E_0 - E_p\).
Thus, the field decreases. The reduced field is \(E = E_0 / K\), where \(K\) is the dielectric constant.
Quick Tip: For conductors, the internal field becomes zero. For dielectrics, it decreases but remains non-zero.
A capacitor of capacitance 1 \(\mu\)F is kept at 1 V potential difference between the plates. The charge on the charged capacitor will be
The relationship between charge (\(Q\)), capacitance (\(C\)), and potential difference (\(V\)) is \(Q = CV\).
Given \(C = 1 \, \muF = 1 \times 10^{-6} \, F\).
Given \(V = 1 \, V\).
\(Q = (1 \, \muF) \times (1 \, V) = 1 \, \muC\).
Quick Tip: \(1 \, \muF = 10^{-6} \, F\). Always check prefixes.
If a charged particle of mass m and charge q enters a uniform magnetic field B at an angle \(\theta\) in the direction of field with velocity v, then the path of the particle is helical. The radius of circular path of the helix will be
The velocity component perpendicular to the magnetic field is \(v_{\perp} = v \sin \theta\).
This perpendicular component is responsible for the circular motion.
The magnetic force provides the centripetal force: \(q v_{\perp} B = \frac{m v_{\perp}^2}{r}\).
Radius \(r = \frac{m v_{\perp}}{qB} = \frac{mv \sin \theta}{qB}\).
Quick Tip: The parallel component \(v \cos \theta\) is responsible for the pitch of the helix.
An ideal ammeter has
An ammeter is connected in series in a circuit to measure current.
To ensure it does not alter the current it is measuring, its resistance must be as low as possible.
For an ideal ammeter, the resistance is defined as zero.
Quick Tip: An ideal Voltmeter (connected in parallel) has Infinite resistance.
Remote control for televisions uses
Television remote controls transmit signals using light emitting diodes (LEDs) that emit Infrared (IR) radiation.
Infrared waves are used because they are invisible to the eye but can be easily detected by sensors on the TV.
Quick Tip: Our eyes can't see IR, but many smartphone cameras can detect the purple/white flash from a remote's IR LED.
The surface charge densities on the surface of two conducting spheres of radii \(r_1\) and \(r_2\) are equal. The ratio of electric field intensities on the surfaces is
The electric field intensity on the surface of a conducting sphere is given by \(E = \frac{\sigma}{\epsilon_0}\).
Here, \(\sigma\) is the surface charge density.
Since \(\sigma\) is given to be equal for both spheres, and \(\epsilon_0\) is a universal constant, the Electric Field \(E\) depends only on \(\sigma\).
Therefore, \(E_1 = E_2\), and the ratio is 1:1.
Quick Tip: \(E\) depends on radius only if Charge \(Q\) is constant (\(E \propto 1/R^2\)). If \(\sigma\) is constant, \(E\) is constant.
Ohm's law does not apply, when
Ohm's law states that \(V \propto I\) provided all physical conditions, especially temperature, remain constant.
Resistance \(R\) changes with temperature.
If the temperature changes, the ratio \(V/I\) is not constant, and Ohm's law is not strictly applicable in its linear form.
Quick Tip: Devices that do not follow Ohm's law are called Non-ohmic devices (e.g., diodes, transistors).
An example of natural electromagnetic induction is
Radio and Television are human-made technologies utilizing electromagnetic waves.
Battery charging is an electrochemical process.
Lightning is a massive natural electrical discharge. The rapid change in current during a lightning strike produces strong changing magnetic fields, which induce electromagnetic currents (EMPs) in nearby conductors. This is a natural manifestation of induction principles.
Quick Tip: The Earth itself acts as a giant magnet, and interactions with solar wind (Aurora) also involve natural electromagnetic phenomena.
Which quantity decreases in step-down transformer?
A transformer is used to change the voltage level of AC.
A step-down transformer decreases the output voltage compared to the input voltage (\(V_{secondary} < V_{primary}\)).
Since Power (\(P=VI\)) is conserved (ideally), if Voltage decreases, Current increases.
Frequency remains unchanged.
Quick Tip: Step-Down: Voltage \(\downarrow\), Current \(\uparrow\). Step-Up: Voltage \(\uparrow\), Current \(\downarrow\).
The refractive index of water is 1.33. What will be the speed of light in water?
Refractive index (\(n\)) = Speed of light in vacuum (\(c\)) / Speed of light in medium (\(v\)).
\(n = 1.33 \approx \frac{4}{3}\).
\(v = \frac{c}{n} = \frac{3 \times 10^8}{4/3}\).
\(v = 3 \times \frac{3}{4} \times 10^8 = \frac{9}{4} \times 10^8 = 2.25 \times 10^8\) m/s.
Quick Tip: Light slows down in denser media. The speed cannot exceed \(3 \times 10^8\) m/s.
The maximum kinetic energy of the photoelectrons varies
Einstein's Photoelectric Equation: \(K_{max} = h\nu - \Phi\).
\(K_{max}\) depends linearly on frequency \(\nu\).
It does not depend on the intensity of light. Intensity determines the \textit{number of photoelectrons emitted, not their energy.
Quick Tip: Below the threshold frequency, no emission occurs regardless of intensity.
Which of the following are known as nucleons?
Nucleons are the particles that reside inside the nucleus of an atom.
The atomic nucleus consists of Protons and Neutrons.
Therefore, protons and neutrons are collectively called nucleons.
Quick Tip: Mass number (A) is the total count of nucleons.
'World Wide Web' was invented by
Sir Tim Berners-Lee invented the World Wide Web (WWW) in 1989.
John Logie Baird is associated with TV, and Marconi with Radio.
Quick Tip: WWW uses HTTP protocol to link documents over the internet.
Which of the following expressions represents electrical energy?
Electrical Power \(P = V \cdot I\).
Electrical Energy \(E = Power \times time = V \cdot I \cdot t\).
Option (C) has a typo (\(I \cdot R^2 \cdot t\) instead of \(I^2 Rt\)) and (D) represents Power. Option (A) is the correct expression for Energy.
Quick Tip: \(E = VIt = I^2 Rt = \frac{V^2}{R}t\). All are valid formulas for energy.
When an alpha-particle is brought towards another alpha-particle, the potential energy of the system
Alpha particles are positively charged (\(+2e\)).
When brought closer, the electrostatic repulsive force acts between them.
Work must be done against this repulsive force to bring them closer.
This work is stored as Electrostatic Potential Energy. \(U = \frac{k q_1 q_2}{r}\). As \(r\) decreases, \(U\) increases.
Quick Tip: Potential energy increases when moving against a conservative force (repulsion).
Dielectric constant of water is
The dielectric constant (Relative Permittivity, \(K\) or \(\epsilon_r\)) of pure water is approximately 80 (specifically 81 at \(20^\circ\)C).
This high value is due to the polar nature of water molecules.
Air/Vacuum is \(\approx 1\). Metals are \(\infty\).
Quick Tip: High dielectric constant explains why water is such a good solvent for ionic compounds (reduces force between ions).
The relationship between current density \(\vec{J}\), specific conductance \(\sigma\) and electric field intensity \(\vec{E}\) is
This is the microscopic or vector form of Ohm's Law.
Current Density \(\vec{J} = \frac{I}{A}\). Electric Field \(\vec{E} = \rho \vec{J}\).
Conductivity \(\sigma = \frac{1}{\rho}\).
Therefore, \(\vec{J} = \sigma \vec{E}\).
Quick Tip: Standard Ohm's law \(V=IR\) is the macroscopic form derived from this relation.
The yellow colour code value of carbon resistance is
Mnemonic: B B R O Y Great Britain Very Good Wife.
Black - 0
Brown - 1
Red - 2
Orange - 3
Yellow - 4
Green - 5
Quick Tip: Remember the sequence: 0 to 9.
Relative permeability is equal to
Absolute permeability (\(\mu\)) of a medium is defined as \(\mu = \mu_r \mu_0\).
Where \(\mu_0\) is permeability of free space and \(\mu_r\) is relative permeability.
Therefore, \(\mu_r = \frac{\mu}{\mu_0}\).
Quick Tip: \(\mu_r\) is a dimensionless quantity. For vacuum, \(\mu_r = 1\).
If a bar magnet is cut into two equal pieces transverse to its length, then each piece will
Cutting a magnet transverse to its length (perpendicular to the axis) results in two smaller magnets.
The pole strength (\(m\)) remains the same.
The length (\(2l\)) is halved to (\(l\)).
Original Magnetic Moment \(M = m \times 2l\).
New Magnetic Moment \(M' = m \times l = \frac{M}{2}\).
Thus, it behaves as a new magnet with reduced (half) magnetic moment.
Quick Tip: Cutting along the axis (longitudinally) halves the pole strength, also resulting in half the magnetic moment.
In an ac circuit of capacitance the current from potential difference is
In a pure capacitive AC circuit, the current (\(I\)) leads the voltage (\(V\)) by a phase angle of \(90^\circ\) (\(\pi/2\)).
"Leading" means the current is "forward" relative to the voltage.
(Conversely, in an inductive circuit, current lags or is backward).
Quick Tip: Mnemonic: ICE (Current I leads in Capacitance C, EMF E leads in Inductance L - ELI).
A capacitor is a perfect insulator for
Capacitive Reactance \(X_C = \frac{1}{2\pi f C}\).
For Direct Current (DC), frequency \(f = 0\).
Therefore, \(X_C = \frac{1}{0} = \infty\).
Infinite resistance implies it acts as a perfect insulator, blocking steady DC current (after charging).
Quick Tip: Capacitors "block DC and pass AC".
The unit of displacement current is
Displacement current is a quantity appearing in Maxwell's equations defined in terms of the rate of change of electric flux.
Physically, it has the same dimension and unit as conduction current.
Its unit is Ampere (A).
Quick Tip: Displacement current makes the path of current continuous across capacitor plates where conduction current is zero.
The solar spectrum is
The light emitted by the sun's core (photosphere) is a continuous spectrum.
However, as it passes through the cooler outer atmosphere of the sun (chromosphere), certain wavelengths are absorbed by the elements present there.
This results in dark lines appearing on the continuous background, known as Fraunhofer lines.
Therefore, it is an absorption spectrum, best described here as a "spectrum of black lines".
Quick Tip: These lines help identify elements present in the sun's atmosphere (e.g., Helium was discovered this way).
The field of view is maximum for
A convex mirror curves outward.
This curvature diverges the light rays, allowing it to capture images from a much wider angle compared to plane or concave mirrors.
This wide field of view is why convex mirrors are used as rear-view mirrors in vehicles.
Quick Tip: Images in a convex mirror are always virtual, erect, and diminished.
The ratio of the refractive index of red light to blue light in air is
According to Cauchy's relation, refractive index \(\mu \propto \frac{1}{\lambda^2}\).
Wavelength of red light (\(\lambda_R\)) is greater than blue light (\(\lambda_B\)).
Therefore, refractive index for red (\(\mu_R\)) is less than that for blue (\(\mu_B\)).
Ratio \(\frac{\mu_R}{\mu_B} < 1\).
Quick Tip: Violet/Blue bends more than Red in a prism because \(\mu_V > \mu_R\).
The momentum (p) of photon is
According to de Broglie's hypothesis and Planck's theory, the momentum \(p\) of a photon or particle is related to its wavelength \(\lambda\).
\(p = \frac{h}{\lambda}\)
Where \(h\) is Planck's constant.
Quick Tip: Energy \(E = h\nu = \frac{hc}{\lambda} = pc\).
The radius of the lowest Bohr's orbit in hydrogen atom is \(r_0\). The radius of Bohr's second orbit is
The radius of the \(n^{th}\) Bohr orbit is given by \(r_n \propto n^2\).
\(r_n = n^2 r_0\) (where \(r_0\) is the radius of the first orbit, \(n=1\)).
For the second orbit, \(n=2\).
\(r_2 = 2^2 \times r_0 = 4r_0\).
Quick Tip: Radii are in ratio 1 : 4 : 9 : 16...
If magnetic field is same but the area of the loop is increased, then the flux
Magnetic Flux \(\phi = B \cdot A \cos \theta\).
If the Magnetic Field \(B\) is constant and the Area \(A\) increases, the product \(BA\) increases.
Therefore, the flux increases.
Quick Tip: Change in flux induces EMF.
The voltage of domestic ac is 220 V. What does this represent?
AC voltages and currents specified in domestic and industrial contexts are always Root Mean Square (RMS) values unless stated otherwise.
220 V is \(V_{rms}\).
Peak voltage \(V_0 = \sqrt{2} \times 220 \approx 311\) V.
(Note: Option C and D are identical in the text provided, both correct).
Quick Tip: RMS value is the DC equivalent that produces the same heating effect.
The wavefront due to a point source at a finite distance from the source is
A point source emits waves in all directions uniformly in 3D space.
The locus of points having the same phase at a finite distance \(r\) is a sphere.
Therefore, the wavefront is spherical.
Quick Tip: As the distance becomes infinite (\(r \to \infty\)), a small portion of the spherical wavefront appears as a Plane Wavefront.
For destructive interference, the path difference should be equal to
Destructive interference (dark fringe) occurs when the two waves meet out of phase.
This happens when the path difference is an odd integral multiple of half wavelength.
\(\Delta x = (2n+1) \frac{\lambda}{2}\) (where \(n = 0, 1, 2...\)).
Constructive interference occurs at \(n\lambda\).
Quick Tip: Odd multiples of \(\lambda/2\) lead to cancellation (Destructive). Integer multiples of \(\lambda\) lead to addition (Constructive).
In an electric field with intensity E = 0, the change of potential V with distance r will be
The relation between Electric Field and Potential is \(E = -\frac{dV}{dr}\).
If \(E = 0\), then \(\frac{dV}{dr} = 0\).
The derivative of a quantity is zero only if the quantity is constant.
Therefore, Potential \(V\) is constant.
Quick Tip: This is why the entire volume of a conductor is at the same potential (Equipotential), as the internal field is zero.
The equivalent resistance of resistors in parallel combination
In parallel combination, the reciprocal of equivalent resistance is the sum of reciprocals of individual resistances: \(\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + ...\)
The equivalent resistance \(R_{eq}\) is always less than the smallest individual resistance in the combination.
Therefore, equivalent resistance decreases compared to individual resistors.
Quick Tip: Series increases resistance (Add); Parallel decreases resistance.
The magnetic field lines inside a current-carrying solenoid are
Inside a long, tightly wound current-carrying solenoid, the magnetic field is uniform.
Uniform magnetic field lines are represented by parallel and equidistant straight lines.
They run along the axis of the solenoid.
Quick Tip: Outside an ideal solenoid, the field is approximately zero.
Coherent sources are those sources for which
Two sources are said to be coherent if they emit waves of the same frequency and have a constant phase difference (independent of time).
While same frequency is a prerequisite, the defining characteristic is the constant phase relationship.
Option (A) is the standard definition found in most physics texts for multiple choice questions. (Note: Option D is also technically true as constant phase difference implies same frequency, but A is the direct definition).
Quick Tip: Independent light sources (two bulbs) can never be coherent.
Natural light from the sun is
Light emitted by thermal sources like the Sun, flames, or bulbs consists of waves vibrating in all possible planes perpendicular to the direction of propagation.
Such light is called unpolarised light.
Quick Tip: Unpolarised light can be polarised using polaroids or by reflection at Brewster's angle.
Radioactivity was discovered by
Radioactivity was accidentally discovered by the French physicist Henri Becquerel in 1896 while working with uranium salts.
Marie and Pierre Curie later coined the term "radioactivity" and discovered Polonium and Radium.
Quick Tip: Becquerel shared the 1903 Nobel Prize with the Curies.
The example of a broadcast mode of communication is
In broadcast mode, a single transmitter sends signals to a large number of receivers simultaneously.
Radio and Television are classic examples of broadcasting.
Telephone is a point-to-point communication mode (one user to another).
Quick Tip: Broadcast is one-to-many; Point-to-point is one-to-one.
Which device is used as a voltage regulator?
A Zener diode is a special purpose p-n junction diode designed to operate in the reverse breakdown region.
In this region, the voltage across the diode remains nearly constant even for large changes in current.
This property is utilized for voltage regulation.
Quick Tip: It is connected in parallel to the load in reverse bias.
When an electric dipole \(\vec{p}\) is placed in a uniform electric field \(\vec{E}\), then at what angle between \(\vec{p}\) and \(\vec{E}\), the value of torque will be maximum?
The torque \(\tau\) acting on a dipole is given by \(\tau = pE \sin \theta\).
Here, \(\theta\) is the angle between dipole moment \(\vec{p}\) and electric field \(\vec{E}\).
Torque is maximum when \(\sin \theta\) is maximum, i.e., \(\sin \theta = 1\).
This corresponds to \(\theta = 90^\circ\).
Quick Tip: At \(0^\circ\) and \(180^\circ\), torque is zero (Equilibrium positions).
A circular loop radius R carries a current I. Its magnetic dipole moment is
The magnetic dipole moment (\(M\)) of a current loop is given by \(M = Current \times Area\).
\(M = I \times A\).
For a circular loop of radius \(R\), Area \(A = \pi R^2\).
So, \(M = I (\pi R^2)\).
Quick Tip: Direction of M is given by Right Hand Thumb Rule.
When the tube length of microscope is increased, its magnifying power
The magnifying power (\(M\)) of a compound microscope is approximately given by \(M = \frac{L}{f_o} \frac{D}{f_e}\).
Here, \(L\) is the tube length (distance between focal points of objective and eyepiece).
Since \(M \propto L\), increasing the tube length increases the magnifying power.
Quick Tip: Usually, tube length is fixed in lab microscopes, but theoretical relation shows proportionality.
Cathode rays are group of
J.J. Thomson experiments showed that cathode rays consist of negatively charged particles.
These particles were later named electrons.
So, cathode rays are streams of high-speed electrons.
Quick Tip: Canal rays (Anode rays) are streams of positive ions.
When a soap bubble is charged, then its size
When a soap bubble is given a charge (positive or negative), the like charges on the surface repel each other.
This electrostatic repulsion creates an outward pressure (mechanical stress).
This outward pressure acts against surface tension and external pressure, causing the bubble to expand in radius.
Quick Tip: \(P_{excess} = \frac{4T}{R} - \frac{\sigma^2}{2\epsilon_0}\). Expansion continues until equilibrium.
If the area of plates of a capacitor is halved, then the capacitance will
The capacitance of a parallel plate capacitor is \(C = \frac{\epsilon_0 A}{d}\).
If the area \(A\) is halved (\(A' = A/2\)), keeping \(d\) constant:
\(C' = \frac{\epsilon_0 (A/2)}{d} = \frac{1}{2} \left( \frac{\epsilon_0 A}{d} \right) = \frac{C}{2}\).
Therefore, capacitance becomes half.
Quick Tip: \(C \propto A\) and \(C \propto 1/d\).
Choke coil works on the principle of
A choke coil is an inductor with high inductance and negligible resistance.
It is used to control current in AC circuits.
It works on the principle of Self Induction, generating a back EMF that opposes the flow of alternating current, thereby limiting it without significant power loss.
(Note: The current flowing is often called wattless current, but the working \textit{principle is self-induction).
Quick Tip: Choke coils are used in tube lights to reduce voltage without heat loss (unlike a resistor).
To remove hypermetropia, lens used is
Hypermetropia (Far-sightedness) is a defect where a person can see distant objects clearly but near objects appear blurry because the image is formed behind the retina.
To correct this, a converging lens is required to converge the rays sooner.
A convex lens is a converging lens.
Quick Tip: Myopia (Near-sightedness) uses Concave lens.
Inverse square law of intensity of light, i.e., intensity \(\propto \frac{1}{r^2}\) is applicable for
For a point source, light spreads out in spherical wavefronts.
The surface area of a sphere is \(4\pi r^2\).
Since energy is conserved, Intensity \(I = \frac{Power}{Area} = \frac{P}{4\pi r^2}\).
Therefore, \(I \propto \frac{1}{r^2}\).
Quick Tip: For a linear source (cylindrical wavefront), \(I \propto 1/r\). For a plane source, \(I\) is constant.
The kinetic energy (K) of an electron in a Bohr orbit is related to its potential energy (U) by
In Bohr's model:
Potential Energy \(U = -\frac{Ze^2}{r}\).
Kinetic Energy \(K = \frac{Ze^2}{2r}\).
Comparing the two: \(U = -2K\) or \(K = -\frac{U}{2}\).
Total Energy \(E = K + U = -K = U/2\).
Quick Tip: Kinetic energy is always positive; Potential and Total energies are negative for bound states.
Semiconductor is damaged by the strong current due to
When a strong current flows through a semiconductor, it causes significant heating.
This thermal energy breaks covalent bonds, generating a massive number of electron-hole pairs (avalanche effect).
The sudden surge in charge carriers ("excess of electrons") leads to a breakdown of the crystal structure and permanent damage.
Quick Tip: This is why appropriate resistors are used to limit current in diode/transistor circuits.
The valency of impurity element to convert a germanium crystal into a p-type semiconductor is
Germanium is a Group 14 element (tetravalent).
To create a p-type (positive type) semiconductor, we need to create holes (electron vacancies).
This is done by doping with a Trivalent impurity (Group 13 elements like Boron, Aluminium, Gallium, Indium).
Trivalent elements have a valency of 3.
Quick Tip: For n-type, Pentavalent (valency 5) impurities are used.
In a communication system, a repeater is
A repeater acts to extend the range of a communication system.
It picks up the signal from the transmitter (acts as a Receiver), amplifies and reconditions it, and then re-transmits it to the receiver (acts as a Transmitter).
Therefore, it is a combination of both.
Quick Tip: Repeaters are essential in optical fiber and mobile networks to overcome signal attenuation.
The maximum velocity of an electron emitted from a metal surface becomes two times when the frequency \(\nu\) of the incident light is doubled. The work function of the metal is
Let the initial frequency be \(\nu\) and max velocity be \(v\).
\(K_1 = \frac{1}{2}mv^2 = h\nu - \Phi\) \quad ...(1)
In the second case, frequency is \(2\nu\) and max velocity is \(2v\).
\(K_2 = \frac{1}{2}m(2v)^2 = 4 (\frac{1}{2}mv^2) = 4K_1\).
\(4K_1 = h(2\nu) - \Phi\) \quad ...(2)
Substitute (1) into (2):
\(4(h\nu - \Phi) = 2h\nu - \Phi\)
\(4h\nu - 4\Phi = 2h\nu - \Phi\)
\(2h\nu = 3\Phi\)
\(\Phi = \frac{2h\nu}{3}\)
Quick Tip: Work function (\(\Phi\)) is a property of the material and does not change with incident light.
Section B
Question 1:
The maximum and minimum amplitudes for an amplitude modulated wave are 12 V and 3 V respectively. Calculate the value of modulation index.
Given:
Maximum amplitude, \(A_{max} = 12\) V
Minimum amplitude, \(A_{min} = 3\) V
The formula for modulation index (\(\mu\)) is:
\(\mu = \frac{A_{max} - A_{min}}{A_{max} + A_{min}}\)
Substituting the values:
\(\mu = \frac{12 - 3}{12 + 3}\)
\(\mu = \frac{9}{15}\)
\(\mu = 0.6\)
So, the modulation index is 0.6.
Quick Tip: The modulation index is a dimensionless quantity and should ideally be \(\le 1\) to avoid distortion.
Define current density.
Current density is defined as the electric current flowing per unit cross-sectional area of a conductor, where the area is held normal to the direction of current flow.
It is a vector quantity denoted by \(\vec{J}\).
Mathematically, if current \(I\) flows through an area \(A\):
\(J = \frac{I}{A}\)
Its SI unit is Ampere per square meter (\(A/m^2\)).
Quick Tip: Current is a scalar quantity, but Current Density is a vector pointing in the direction of the electric field (\( \vec{J} = \sigma \vec{E} \)).
What is Malus's law?
Malus's law states that when a beam of completely plane-polarized light is incident on an analyzer, the intensity (\(I\)) of the light transmitted through the analyzer is directly proportional to the square of the cosine of the angle (\(\theta\)) between the transmission axes of the polarizer and the analyzer.
Mathematically:
\(I = I_0 \cos^2 \theta\)
Where \(I_0\) is the maximum intensity of the incident polarized light.
Quick Tip: When \(\theta = 90^\circ\) (Crossed Polaroids), the transmitted intensity is zero.
How are electromagnetic waves different from sound waves? Write any two differences.
Two major differences are:
1. Medium Requirement: Electromagnetic waves do not require any material medium for propagation (can travel through vacuum), whereas sound waves are mechanical waves and strictly require a material medium (solid, liquid, or gas) to travel.
2. Nature of Wave: Electromagnetic waves are transverse in nature (oscillations are perpendicular to propagation), while sound waves in air are longitudinal (oscillations are parallel to propagation).
(Additional difference: Speed of EM waves is \(3 \times 10^8\) m/s, while sound is \(\approx 340\) m/s).
Quick Tip: Light is an EM wave; hence we can see the sun. Sound is a mechanical wave; hence we cannot hear explosions in space.
What is the use of a step-up transformer?
A step-up transformer is used to increase the alternating voltage from a lower value to a higher value.
Its primary use is in Power Transmission.
At power generating stations, step-up transformers are used to increase the voltage to very high levels (e.g., 132 kV, 220 kV) before transmission.
This reduces the current for a given power level (\(P=VI\)), thereby significantly reducing the \(I^2R\) heat losses in transmission lines.
Quick Tip: In a step-up transformer, the number of turns in the secondary coil is greater than in the primary coil (\(N_S > N_P\)).
What is wattless current?
Wattless current refers to the current flowing in an AC circuit when the average power consumed by the circuit is zero.
This happens in a purely inductive or purely capacitive circuit where the phase difference (\(\phi\)) between voltage and current is \(90^\circ\) or \(\pi/2\).
Since Average Power \(P = V_{rms} I_{rms} \cos \phi\), and \(\cos(90^\circ) = 0\), the power dissipated is zero despite current flowing. This component of current (\(I \sin \phi\)) is called wattless or idle current.
Quick Tip: Choke coils use this principle to limit current without power loss.
Define half-life. State the relation between half-life and decay constant.
Definition: Half-life (\(T_{1/2}\)) of a radioactive substance is defined as the time interval during which the number of undecayed nuclei reduces to exactly one-half of its initial value.
Relation: The half-life is inversely proportional to the decay constant (\(\lambda\)).
\(T_{1/2} = \frac{\ln 2}{\lambda} = \frac{0.693}{\lambda}\)
Quick Tip: After \(n\) half-lives, the amount remaining is \((1/2)^n\) of the original amount.
Write the unit and dimensional formula of permittivity of free space.
From Coulomb's Law, \(F = \frac{1}{4\pi\epsilon_0} \frac{q_1 q_2}{r^2}\).
Rearranging for \(\epsilon_0\): \(\epsilon_0 = \frac{q_1 q_2}{4\pi F r^2}\).
SI Unit: \(\frac{C \cdot C}{N \cdot m^2} = C^2 N^{-1} m^{-2}\) (Coulomb square per Newton per meter square).
(Also Farad/meter).
Dimensional Formula:
Charge \(q = [AT]\)
Force \(F = [MLT^{-2}]\)
Distance \(r = [L]\)
\([\epsilon_0] = \frac{[AT][AT]}{[MLT^{-2}][L^2]} = [M^{-1} L^{-3} T^4 A^2]\).
Quick Tip: Permittivity (\(\epsilon_0\)) is related to the speed of light by \(c = 1/\sqrt{\mu_0 \epsilon_0}\).
What will be the effect on resistance of a metallic conductor and a semiconductor on increasing the temperature? Explain with reasons.
Metallic Conductor: Resistance Increases.
\textit{Reason: As temperature rises, the thermal vibration of lattice ions increases. This increases the frequency of collisions between free electrons and ions, decreasing the relaxation time (\(\tau\)). Since \(R \propto 1/\tau\), resistance increases.
Semiconductor: Resistance Decreases.
\textit{Reason: As temperature rises, covalent bonds break, generating more electron-hole pairs. This significantly increases the number density of charge carriers (\(n\)). Since conductivity \(\sigma \propto n\), the resistance decreases (negative temperature coefficient).
Quick Tip: Metals have a positive temperature coefficient of resistivity (\(\alpha\)), while semiconductors have a negative \(\alpha\).
Explain sky waves and space waves.
Sky Waves: These are radio waves in the frequency range of 3 MHz to 30 MHz. They are used for long-distance communication by being reflected back to Earth by the ionosphere (electrically charged layers in the atmosphere).
Space Waves: These are high-frequency radio waves (above 40 MHz) that travel in a straight line from the transmitting antenna to the receiving antenna (Line-of-Sight propagation). They are used for Television broadcast, Radar, and FM radio. They do not get reflected by the ionosphere.
Quick Tip: Space wave propagation is limited by the curvature of the earth (Horizon).
Write truth table and Boolean expression of OR and AND gates.
1. OR Gate:
Boolean Expression: \(Y = A + B\)
Truth Table:
2. AND Gate:
Boolean Expression: \(Y = A \cdot B\)
Truth Table:
Quick Tip: OR is logical addition (any input High \(\to\) Output High). AND is logical multiplication (both inputs High \(\to\) Output High).
What are donor and acceptor impurities?
Donor Impurities: These are pentavalent elements (Group 15, valency 5) like Arsenic (As), Phosphorus (P), or Antimony (Sb). When doped into a semiconductor (Si/Ge), each atom donates one free electron to the crystal, creating n-type semiconductors.
Acceptor Impurities: These are trivalent elements (Group 13, valency 3) like Boron (B), Indium (In), or Aluminium (Al). When doped, each atom creates a vacancy (hole) in the bond lattice to accept an electron, creating p-type semiconductors.
Quick Tip: Remember: "Donor" Donates electrons (n-type). "Acceptor" Accepts electrons/creates holes (p-type).
Define ionization energy. What is its value for hydrogen atom?
Definition: Ionization energy is the minimum amount of energy required to remove an electron from the ground state (\(n=1\)) of an isolated gaseous atom to infinity (outside the influence of the nucleus).
For the Hydrogen atom, the ground state energy is \(-13.6\) eV.
Therefore, the energy required to remove the electron is:
\(E_{\infty} - E_{1} = 0 - (-13.6 eV) = +13.6 eV\).
Value: The ionization energy of a hydrogen atom is 13.6 eV.
Quick Tip: It is equivalent to the ionization potential of 13.6 Volts.
What is the difference between magnification and magnifying power?
Magnification (Linear Magnification, m): It is the ratio of the linear size of the image (\(h'\)) to the linear size of the object (\(h\)). It relates to how large the image physically is compared to the object. Formula: \(m = h'/h = v/u\).
Magnifying Power (Angular Magnification, M): Used for optical instruments (microscopes/telescopes). It is the ratio of the angle subtended by the image at the eye (\(\beta\)) to the angle subtended by the object at the unaided eye (\(\alpha\)). It relates to how large the object \textit{appears to the eye. Formula: \(M = \beta/\alpha\).
Quick Tip: For a telescope, linear magnification of the distant object is nearly zero, but magnifying power is high (it brings the image closer angularly).
What is spherical aberration?
Spherical aberration is an optical defect observed in spherical mirrors and lenses with large apertures.
It arises because rays striking the outer edges (marginal rays) are focused at a different point closer to the optic center than the rays striking near the center (paraxial rays).
This inability to focus all parallel rays to a single point results in a blurred or fuzzy image.
Quick Tip: This defect is minimized by using parabolic mirrors (in telescopes/headlights) or stopping down the aperture.
Write the expression for power factor of LCR circuit.
The power factor (\(\cos \phi\)) of a series LCR AC circuit is defined as the ratio of resistance to impedance.
Expression:
\(Power Factor (\cos \phi) = \frac{R}{Z}\)
Substituting the value of Impedance (\(Z\)):
\(\cos \phi = \frac{R}{\sqrt{R^2 + (X_L - X_C)^2}}\)
Where \(R\) is Resistance, \(X_L\) is Inductive Reactance (\(\omega L\)), and \(X_C\) is Capacitive Reactance (\(1/\omega C\)).
Quick Tip: At resonance, \(X_L = X_C\), so \(Z=R\) and Power Factor = 1 (Maximum).
What is Lorentz force?
Lorentz force is the total force experienced by a charged particle moving in a region where both electric and magnetic fields are present.
It is the vector sum of the electric force (\(\vec{F}_e\)) and the magnetic force (\(\vec{F}_m\)).
Mathematical Expression:
\(\vec{F} = \vec{F}_e + \vec{F}_m\)
\(\vec{F} = q\vec{E} + q(\vec{v} \times \vec{B})\)
Where \(q\) is charge, \(\vec{v}\) is velocity, \(\vec{E}\) is electric field, and \(\vec{B}\) is magnetic field.
Quick Tip: If a particle moves undeflected in crossed fields, \(qE = qvB\), so velocity selector \(v = E/B\).
Write any two characteristics of matter waves.
1. Wavelength Relation: The wavelength of a matter wave is inversely proportional to the momentum of the particle (\(\lambda = h/p = h/mv\)). Lighter particles moving slower have longer wavelengths.
2. Not Electromagnetic: Matter waves are not electromagnetic in nature. They are associated with moving material particles, whether charged or uncharged. They are probability waves (Schr\"{odinger waves).
(Other characteristic: They depend on the frame of reference).
Quick Tip: Matter waves are significant only for microscopic particles (electrons); for macroscopic objects, \(\lambda\) is too small to detect.
Differentiate between primary and secondary rainbows.
Primary Rainbow:
1. Formed by two refractions and one internal reflection of sunlight within raindrops.
2. Colors are brighter/intense.
3. Outer edge is Red, inner edge is Violet.
Secondary Rainbow:
1. Formed by two refractions and two internal reflections of sunlight within raindrops.
2. Colors are fainter (less intense) due to light loss in the extra reflection.
3. Order of colors is reversed: Outer edge is Violet, inner edge is Red.
Quick Tip: The primary rainbow appears at an angle of roughly \(42^\circ\), while the secondary appears higher at about \(51^\circ\).
What are '\(\alpha\)' and '\(\beta\)' parameters of transistor? What is their relation?
These are current amplification factors (current gains).
\(\mathbf{\alpha}\) (alpha): It is the DC current gain in Common Base (CB) configuration. It is the ratio of collector current to emitter current. \(\alpha = I_C / I_E\). (Value is slightly \(< 1\)).
\(\mathbf{\beta}\) (beta): It is the DC current gain in Common Emitter (CE) configuration. It is the ratio of collector current to base current. \(\beta = I_C / I_B\). (Value is large, typically 20-100).
Relation:
Since \(I_E = I_C + I_B\), dividing by \(I_C\) leads to the relation:
\(\beta = \frac{\alpha}{1 - \alpha}\) \quad or \quad \(\alpha = \frac{\beta}{1 + \beta}\).
Quick Tip: Common Emitter is preferred for amplifiers because it provides high current gain (\(\beta\)) compared to Common Base (\(\alpha \approx 1\)).
Derive an expression for torque experienced by electric dipole placed in external electric field.
Consider an electric dipole consisting of charges \(+q\) and \(-q\) separated by distance \(2a\).
Let it be placed in a uniform external electric field \(\vec{E}\), making an angle \(\theta\) with the field direction.
1. Force on charge \(+q\): \(\vec{F}_+ = q\vec{E}\) (along \(\vec{E}\)).
2. Force on charge \(-q\): \(\vec{F}_- = -q\vec{E}\) (opposite to \(\vec{E}\)).
The net force is zero, but the forces act along different lines of action, forming a couple. This produces a torque (\(\tau\)).
\(Torque = Magnitude of either force \times Perpendicular distance between forces\).
Perpendicular distance \(= 2a \sin \theta\).
\(\tau = (qE) \times (2a \sin \theta)\)
\(\tau = (q \times 2a) E \sin \theta\)
Since Dipole Moment \(p = q \times 2a\):
\(\tau = p E \sin \theta\)
In vector form:
\(\vec{\tau} = \vec{p} \times \vec{E}\)
Quick Tip: The torque tries to align the dipole with the electric field (\(\theta = 0^\circ\)).
Find the expression of the comparison of e.m.f.s of two cells by a potentiometer.
A potentiometer works on the principle that the potential drop across a wire is directly proportional to its length (\(V = k l\)), provided constant current flows.
Method:
1. A primary circuit maintains a constant current in the potentiometer wire.
2. The first cell of emf \(\epsilon_1\) is connected in the secondary circuit. The balancing length \(l_1\) is found where the galvanometer shows zero deflection.
According to the principle: \(\epsilon_1 = k l_1\) \quad ...(i)
(where \(k\) is potential gradient).
3. Now, the second cell of emf \(\epsilon_2\) is connected (replacing the first). The new balancing length \(l_2\) is found.
\(\epsilon_2 = k l_2\) \quad ...(ii)
4. Dividing equation (i) by (ii):
\(\frac{\epsilon_1}{\epsilon_2} = \frac{k l_1}{k l_2}\)
\(\frac{\epsilon_1}{\epsilon_2} = \frac{l_1}{l_2}\)
This gives the ratio of the EMFs of the two cells.
Quick Tip: Potentiometer is preferred over voltmeter because it draws no current from the cell at the null point, measuring the true EMF.
Draw a ray diagram to show the refraction of light through glass prism. Derive the formula for the determination of refractive index of the material of the prism.
Derivation:
From geometry of quadrilateral and triangles:
\(A + \angle QNR = 180^\circ\) and \(r_1 + r_2 + \angle QNR = 180^\circ \implies r_1 + r_2 = A\).
Total deviation \(\delta = (i - r_1) + (e - r_2) = (i + e) - (r_1 + r_2) = i + e - A\).
Minimum Deviation Condition:
The deviation is minimum (\(\delta_m\)) when the ray passes symmetrically, i.e., \(i = e\) and \(r_1 = r_2 = r\).
Substitute into relations:
1. \(r + r = A \implies 2r = A \implies r = \frac{A}{2}\).
2. \(\delta_m = i + i - A \implies 2i = A + \delta_m \implies i = \frac{A + \delta_m}{2}\).
Prism Formula:
Using Snell's Law (\(\mu = \frac{\sin i}{\sin r}\)):
\(\mu = \frac{\sin \left( \frac{A + \delta_m}{2} \right)}{\sin \left( \frac{A}{2} \right)}\)
Quick Tip: This formula is used in spectrometers to measure refractive index accurately.
What are energy bands? How are these formed? Distinguish between conductors, semiconductors and insulators on the basis of formation of the energy bands.
Energy Bands: In a solid crystal, the closely spaced energy levels of electrons form continuous ranges called energy bands.
Formation: In a single atom, electrons have discrete energy levels. When atoms come together to form a solid, the outer (valence) orbitals interact and split into multiple closely spaced levels, forming bands (Valence Band and Conduction Band).
Distinction:
1. Conductors (Metals):
- The Valence Band (VB) and Conduction Band (CB) overlap, or the CB is partially filled.
- There is no Forbidden Energy Gap (\(E_g \approx 0\)). Electrons can easily move to CB.
2. Semiconductors:
- There is a small Forbidden Energy Gap (\(E_g < 3\) eV). (e.g., Si \(\approx 1.1\) eV).
- At 0K, it behaves as an insulator. At room temp, some electrons gain energy to jump to CB.
3. Insulators:
- There is a large Forbidden Energy Gap (\(E_g > 3\) eV). (e.g., Diamond \(\approx 6\) eV).
- Electrons cannot jump from VB to CB, so no conduction occurs.
Quick Tip: Temperature increases conductivity in semiconductors (more jumps) but decreases it in metals (more collisions).
Mention the defects of human vision and describe the method to remove them.
The common vision defects are:
1. Myopia (Near-sightedness):
- \textit{Defect: The person can see near objects clearly but distant objects are blurred. Image forms in front of the retina.
- \textit{Correction: Use a Concave lens of appropriate focal length to diverge rays before they enter the eye.
2. Hypermetropia (Far-sightedness):
- \textit{Defect: The person can see distant objects clearly but near objects are blurred. Image forms behind the retina.
- \textit{Correction: Use a Convex lens to converge rays effectively.
3. Presbyopia:
- \textit{Defect: Loss of power of accommodation (ciliary muscles weaken) due to aging. Both near and far points are affected.
- \textit{Correction: Use a Bifocal lens (upper concave for far, lower convex for near).
4. Astigmatism:
- \textit{Defect: Cornea has different curvature in different planes. Lines in one direction appear sharp while orthogonal ones blur.
- \textit{Correction: Use a Cylindrical lens.
Quick Tip: Power of lens \(P = 1/f\) (meters). Myopia needs negative power; Hypermetropia needs positive.
Derive an expression for the average value of alternating current.
The average value (mean value) of Alternating Current (\(I_{avg}\)) is defined over a positive half-cycle (\(0\) to \(T/2\)), because the average over a full cycle is zero.
Let AC current be \(I = I_0 \sin \omega t\).
Average current \(I_{avg} = \frac{Total Charge}{Total Time} = \frac{\int_0^{T/2} I dt}{\int_0^{T/2} dt}\).
Denominator: \(\int_0^{T/2} dt = [t]_0^{T/2} = \frac{T}{2}\).
Numerator: \(\int_0^{T/2} I_0 \sin \omega t \, dt = I_0 \left[ \frac{-\cos \omega t}{\omega} \right]_0^{T/2}\)
\(= \frac{-I_0}{\omega} [\cos(\frac{2\pi}{T} \cdot \frac{T}{2}) - \cos 0]\)
\(= \frac{-I_0}{\omega} [\cos \pi - 1] = \frac{-I_0}{\omega} [-1 - 1] = \frac{2I_0}{\omega}\).
Since \(\omega = \frac{2\pi}{T}\), Numerator \(= \frac{2I_0 T}{2\pi} = \frac{I_0 T}{\pi}\).
Now, divide Numerator by Denominator:
\(I_{avg} = \frac{I_0 T / \pi}{T / 2} = \frac{2 I_0}{\pi}\).
Value: \(I_{avg} \approx 0.637 I_0\).
Quick Tip: Similarly, for RMS value, the integration is over a full cycle of \(I^2\), giving \(I_{rms} = I_0 / \sqrt{2}\).
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