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UP Board Class 10 Science (Code 824 IK) Question Paper 2024 Available : Download Solution PDF With Answer Key

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Devanshi Mittal

Content Writer | Updated On - Feb 26, 2025

UP Board Class 10 Science Question Paper 2024 PDF (Code 824 IK) is available for download here. The Science exam was conducted on February 29, 2024 in the Morning Shift from 8:30 AM to 11:45 AM. The total marks for the theory paper are 70. Students reported the paper to be moderate.

UP Board Class 10 Science Question Paper 2024 (Code 824 IK) with Solutions

UP Board Class 10 Science Question Paper With Answer Key download iconDownload Check Solution


UP Board Class 10 Science Question Paper With Solution


Part–A
(Sub-Section 1)
Multiple Choice Type Questions

Question 1:

The image of an object placed between the pole and the focus of a concave mirror is formed:

  • (A) Erect, virtual, small.
  • (B) Erect, virtual, large.
  • (C) Erect, real, large.
  • (D) Erect, real, small.
Correct Answer: (B) Erect, virtual, large.
View Solution



When an object is placed between the pole and the focus of a concave mirror, the image formed is erect, virtual, and larger than the object. This occurs because the reflected rays diverge and appear to come from a point behind the mirror, forming a magnified virtual image.
Quick Tip: Concave mirrors can form both real and virtual images depending on the position of the object.


Question 2:

Which lens is used in correcting the defect of long-sightedness (far-sightedness)?

  • (A) Concave lens.
  • (B) Convex lens.
  • (C) Bifocal lens.
  • (D) None of these.
Correct Answer: (B) Convex lens.
View Solution



A convex lens is used to correct long-sightedness (hypermetropia). It helps focus light rays properly onto the retina by converging the light before it enters the eye.
Quick Tip: Hypermetropia (far-sightedness) occurs when the eye cannot focus on nearby objects, requiring a convex lens for correction.


Question 3:

The magnification of the virtual image of an object placed at a distance of 0.2 m from the lens is 0.5. The lens will be:

  • (A) A concave lens of focal length 1 m.
  • (B) A concave lens of focal length 0.2 m.
  • (C) A convex lens of focal length 0.1 m.
  • (D) A convex lens of focal length 0.2 m.
Correct Answer: (B) A concave lens of focal length 0.2 m.
View Solution




Given:
- The object distance \( u = -0.2 \, m \) (negative because the object is placed on the same side as the incident light).
- The magnification \( M = 0.5 \).
- The image is virtual, which implies a positive magnification for a concave lens.

### Step 1: Use the magnification formula
The magnification \( M \) for a lens is given by the formula: \[ M = \frac{v}{u} \]
Where:
- \( v \) is the image distance.
- \( u \) is the object distance.

Substitute the known values: \[ 0.5 = \frac{v}{-0.2} \]
Solving for \( v \): \[ v = 0.5 \times (-0.2) = -0.1 \, m \]
Thus, the image distance \( v = -0.1 \, m \). The negative sign indicates that the image is virtual and formed on the same side as the object (characteristic of concave lenses).

### Step 2: Use the lens formula to find the focal length
The lens formula is: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
Where:
- \( f \) is the focal length of the lens.
- \( v \) is the image distance.
- \( u \) is the object distance.

Substitute the known values \( v = -0.1 \, m \) and \( u = -0.2 \, m \): \[ \frac{1}{f} = \frac{1}{-0.1} - \frac{1}{-0.2} \] \[ \frac{1}{f} = -10 + 5 = -5 \]
Therefore: \[ f = \frac{1}{-5} = -0.2 \, m \]
The negative focal length indicates that the lens is a concave lens.

### Step 3: Conclusion
Thus, the lens is a concave lens with a focal length of \( 0.2 \, m \).

The correct answer is: \[ \boxed{(B) A concave lens of focal length 0.2 m.} \] Quick Tip: Concave lenses always form virtual, upright, and diminished images, whereas convex lenses can form both real and virtual images.


Question 4:

When white light passes through a prism of glass, the colour of a light ray bent maximum towards the base of the prism is:

  • (A) Blue.
  • (B) Red.
  • (C) Green.
  • (D) Violet.
Correct Answer: (D) Violet.
View Solution



When white light passes through a prism, dispersion occurs, and different colors bend at different angles. Violet light bends the most due to its shortest wavelength among visible light.
Quick Tip: Dispersion of light in a prism leads to the formation of a spectrum, with violet bending the most and red bending the least.


Question 5:

Two wires of resistances \(R_1\) and \(R_2\) are joined in parallel. Their equivalent resistance will be:

  • (A) \((R_1 + R_2)\).
  • (B) \((R_1 \times R_2)\).
  • (C) \(\frac{R_1 \times R_2}{R_1 + R_2}\).
  • (D) \(\frac{R_1 + R_2}{R_1 \times R_2}\).
Correct Answer: (C) \(\frac{R_1 \times R_2}{R_1 + R_2}\).
View Solution



For resistors in parallel, the equivalent resistance formula is: \[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} \]
which simplifies to: \[ R_{eq} = \frac{R_1 \times R_2}{R_1 + R_2} \] Quick Tip: In a parallel circuit, the total resistance is always less than the smallest individual resistance.


Question 6:

The filament in an electric bulb is made of:

  • (A) Nichrome.
  • (B) Iron.
  • (C) Tungsten.
  • (D) Constantan.
Correct Answer: (C) Tungsten.
View Solution



Tungsten is used as the filament in an electric bulb because it has a high melting point (around 3400°C) and high resistivity, allowing it to emit bright light when heated.
Quick Tip: Tungsten filaments are chosen due to their ability to withstand high temperatures without melting.


Question 7:

The transformation in an electric cell is:

  • (A) Chemical energy to Electrical energy.
  • (B) Electrical energy to Mechanical energy.
  • (C) Mechanical energy to Electrical energy.
  • (D) Electrical energy to Chemical energy.
Correct Answer: (A) Chemical energy to Electrical energy.
View Solution



An electric cell converts chemical energy into electrical energy through a redox reaction inside the cell, where electrons move from the negative electrode to the positive electrode.
Quick Tip: A battery operates by converting stored chemical energy into electrical energy used to power devices.


Question 8:

In the chemical reaction, \(2 FeCl_3 + 2 H_2O + Y \rightarrow 2 FeCl_2 + H_2SO_4 + 2 HCl\), Y is:

  • (A) S.
  • (B) H\(_2\)S.
  • (C) SO\(_2\).
  • (D) Cl\(_2\).
Correct Answer: (C) SO\(_2\).
View Solution



The given reaction represents the reduction of ferric chloride (\(FeCl_3\)) to ferrous chloride (\(FeCl_2\)) with sulfur dioxide (\(SO_2\)) acting as the reducing agent. In this reaction, sulfur dioxide reduces ferric chloride (\(FeCl_3\)) to ferrous chloride (\(FeCl_2\)), and itself gets oxidized to sulfuric acid (\(H_2SO_4\)). The reaction proceeds as: \[ 2 FeCl_3 + SO_2 + 2 H_2O \rightarrow 2 FeCl_2 + H_2SO_4 + 2 HCl \]
Thus, Y is \( SO_2 \).
Quick Tip: Sulfur dioxide (\(SO_2\)) is commonly used as a reducing agent in inorganic chemistry, especially in the reduction of metal chlorides.


Question 9:

Which of the following is an acidic salt?

  • (A) NaCl.
  • (B) NaHSO\(_4\).
  • (C) Na\(_2\)SO\(_4\).
  • (D) KCN.
Correct Answer: (B) NaHSO\(_4\).
View Solution



An acidic salt is formed when a strong acid and a weak base react. Sodium bisulfate (\(NaHSO_4\)) is an acidic salt because it contains an ionizable hydrogen ion (\(H^+\)), making the solution acidic.
Quick Tip: Acidic salts form when a polybasic acid (like sulfuric acid) is only partially neutralized by a base.


Question 10:

Matte mainly consists of:

  • (A) FeS.
  • (B) Cu\(_2\)S.
  • (C) Cu\(_2\)S and FeS.
  • (D) Cu\(_2\)S and Fe\(_2\)S\(_3\).
Correct Answer: (C) Cu\(_2\)S and FeS.
View Solution



Matte is a molten phase mainly composed of copper sulfide (Cu\(_2\)S) and iron sulfide (FeS), formed during the smelting of copper ores. It is an intermediate product in the extraction of copper.
Quick Tip: Matte is further processed to extract pure copper by oxidation and reduction methods.


Question 11:

Complete the following chemical equation: \[ \_\_\_\_ + PCl_5 \rightarrow CH_3COCl + POCl_3 + HCl \]

  • (A) CH\(_3\)OH.
  • (B) CH\(_3\)COOH.
  • (C) C\(_2\)H\(_5\)OH.
  • (D) CH\(_3\)CH\(_2\)COOH.
Correct Answer: (B) CH\(_3\)COOH.
View Solution



The reaction given is the conversion of acetic acid (CH\(_3\)COOH) into acetyl chloride (CH\(_3\)COCl) using phosphorus pentachloride (PCl\(_5\)). The complete reaction is: \[ CH_3COOH + PCl_5 \rightarrow CH_3COCl + POCl_3 + HCl \]
Acetyl chloride is an important reagent in organic synthesis.
Quick Tip: PCl\(_5\) is commonly used to convert carboxylic acids into acyl chlorides.


Question 12:

Which of the following is an amphoteric oxide?

  • (A) Na\(_2\)O.
  • (B) MgO.
  • (C) Al\(_2\)O\(_3\).
  • (D) P\(_2\)O\(_5\).
Correct Answer: (C) Al\(_2\)O\(_3\).
View Solution



An amphoteric oxide is one that reacts with both acids and bases. Aluminum oxide (Al\(_2\)O\(_3\)) exhibits this behavior: \[ Al_2O_3 + 6HCl \rightarrow 2AlCl_3 + 3H_2O \] \[ Al_2O_3 + 2NaOH + 3H_2O \rightarrow 2Na[Al(OH)_4] \] Quick Tip: Al\(_2\)O\(_3\) is found in bauxite and is used in aluminum extraction.


Question 13:

Chemical formula of propane is:

  • (A) CH\(_4\).
  • (B) C\(_3\)H\(_8\).
  • (C) C\(_4\)H\(_{10}\).
  • (D) C\(_2\)H\(_6\).
Correct Answer: (B) C\(_3\)H\(_8\).
View Solution



Propane (C\(_3\)H\(_8\)) is a hydrocarbon belonging to the alkane family. It consists of three carbon atoms bonded with hydrogen in a single-bonded structure. Propane is widely used as a fuel for heating and cooking. Quick Tip: Alkanes follow the general formula C\(_n\)H\(_{2n+2}\).


Question 14:

Reproduction in Hydra occurs by:

  • (A) Budding.
  • (B) Fission.
  • (C) Fragmentation.
  • (D) Vegetative propagation.
Correct Answer: (A) Budding.
View Solution



Hydra reproduces asexually by budding. A small outgrowth called a bud forms on the parent body. It gradually grows and develops into a new individual, eventually detaching from the parent. This type of reproduction allows Hydra to multiply efficiently.
Quick Tip: \textbf{Budding} is a common asexual reproduction method found in simple organisms like Hydra and yeast.


Question 15:

The process of breakdown of pyruvate takes place in:

  • (A) Cytoplasm.
  • (B) Mitochondria.
  • (C) Chloroplast.
  • (D) Nucleus.
Correct Answer: (B) Mitochondria.
View Solution



Pyruvate breakdown occurs in the mitochondria during aerobic respiration. The pyruvate is converted into Acetyl-CoA, which enters the Krebs cycle, producing ATP, NADH, and FADH\(_2\). This process is essential for energy production in cells.
Quick Tip: The \textbf{mitochondria} are known as the "powerhouse of the cell" because they generate ATP through aerobic respiration.


Question 16:

The kidneys in human beings are a part of which system?

  • (A) Nutrition.
  • (B) Respiration.
  • (C) Excretion.
  • (D) Transportation.
Correct Answer: (C) Excretion.
View Solution



Kidneys are part of the excretory system. They filter waste materials like urea, excess salts, and water from the blood and excrete them as urine. This process helps maintain body fluid balance and removes toxins.
Quick Tip: The \textbf{excretory system} includes the kidneys, ureters, bladder, and urethra, which work together to remove waste from the body.


Question 17:

Mendel got his primary education in:

  • (A) Temple.
  • (B) School.
  • (C) Gurukul.
  • (D) Monastery.
Correct Answer: (B) School.
View Solution



Gregor Mendel received his primary education in a school. Later, he joined a monastery where he carried out his famous genetic experiments on pea plants, leading to the discovery of the fundamental laws of inheritance.
Quick Tip: Mendel is known as the \textbf{"Father of Genetics"} for his pioneering work on inheritance.


Question 18:

Loop is placed in which part of the female reproductive system?

  • (A) Ovary.
  • (B) Oviduct.
  • (C) Uterus.
  • (D) Vagina.
Correct Answer: (C) Uterus.
View Solution



A loop or intrauterine device (IUD) is placed in the uterus as a contraceptive measure to prevent pregnancy. It acts as a physical barrier to implantation and can also release hormones to regulate fertility.
Quick Tip: IUDs are one of the most effective long-term reversible contraceptive methods.


Question 19:

Which of the following organ represents the male reproductive organ in plants?

  • (A) Gynoecium.
  • (B) Stamens.
  • (C) Stigma.
  • (D) Ovary.
Correct Answer: (B) Stamens.
View Solution



The stamen is the male reproductive organ of a flower. It consists of the anther, which produces pollen grains, and the filament, which supports the anther. Pollen grains contain male gametes necessary for fertilization.
Quick Tip: The \textbf{carpel (pistil)} represents the female reproductive organ in plants.


Question 20:

Which of the following is/are called environment-friendly practice(s)?

  • (A) Carrying cloth bags while going to the market for keeping purchased items.
  • (B) Switching off lights and fans to avoid unnecessary consumption of energy.
  • (C) Walking to school on foot instead of going by vehicle.
  • (D) All of the above.
Correct Answer: (D) All of the above.
View Solution



Environment-friendly practices include reducing plastic use, conserving energy, and minimizing carbon footprint. Carrying cloth bags reduces plastic waste, switching off electrical appliances conserves energy, and walking instead of using vehicles decreases air pollution.
Quick Tip: \textbf{Reduce, Reuse, and Recycle} are the three essential principles of environmental conservation.


Question 21:

At what distance should an object be placed from a concave mirror of focal length 10 cm, so that a real image 5 times larger is formed? Also, find the position of the image.

Correct Answer:
View Solution



Let the object distance be \( u \) and the image distance be \( v \). Given that the magnification \( m \) is -5 for a real and inverted image, we use: \[ m = \frac{-v}{u} \] \[ v = -5u \]
Using the mirror formula: \[ \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \]
Substituting \( f = -10 \) cm and \( v = -5u \): \[ \frac{1}{-10} = \frac{1}{u} + \frac{1}{-5u} \]
Solving, we get \( u = -12 \) cm and \( v = -60 \) cm.
Quick Tip: A real and inverted image means the image distance is negative.


Question 22:

The focal length of a convex lens is 50 cm. State the position of the image of an object placed at a distance of 25 cm, perpendicularly on its axis. Also, determine the magnification of the image.

Correct Answer:
View Solution



Using the lens formula: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
Given \( f = 50 \) cm and \( u = -25 \) cm: \[ \frac{1}{50} = \frac{1}{v} - \frac{1}{-25} \] \[ \frac{1}{v} = \frac{1}{50} - \frac{1}{25} = \frac{1}{50} - \frac{2}{50} = \frac{-1}{50} \] \[ v = -50 cm \]
The image is formed at -50 cm, meaning it is virtual and on the same side as the object.

Magnification is given by: \[ m = \frac{v}{u} = \frac{-50}{-25} = 2 \]
Thus, the image is magnified and erect.
Quick Tip: A negative image distance in convex lenses indicates a virtual image.


Question 23:

The resistances 2Ω, 3Ω, and 5Ω are joined in series. If the two ends of the combination are joined to a potential difference of 30 volts, then find the potential difference between the ends of each resistance.

Correct Answer:
View Solution



In a series circuit, the same current flows through all resistors. Using Ohm’s law: \[ V = IR \]
Total resistance: \[ R_{total} = 2 + 3 + 5 = 10Ω \]
Total current: \[ I = \frac{V}{R_{total}} = \frac{30}{10} = 3A \]
Voltage drop across each resistor: \[ V_1 = IR_1 = (3)(2) = 6V \] \[ V_2 = IR_2 = (3)(3) = 9V \] \[ V_3 = IR_3 = (3)(5) = 15V \]
Thus, the potential differences across 2Ω, 3Ω, and 5Ω resistors are 6V, 9V, and 15V, respectively.
Quick Tip: In a series circuit, the sum of individual voltage drops equals the total supplied voltage.


Question 24:

Write down the working and colours of the insulation of the wires used in the domestic electrical distribution circuit:

(i) Live wire

(ii) Earthing wire

(iii) Neutral wire

Correct Answer:
View Solution



The domestic electrical distribution circuit consists of three main types of wires:


- Live Wire: This wire carries the current from the supply to the electrical appliance. It is typically red or brown in color.

- Neutral Wire: It completes the circuit by carrying the current back to the power source. It is usually black or blue in color.

- Earthing Wire: This wire provides safety by preventing electric shocks. It carries leakage current to the ground and is generally green or yellow-green in color.
Quick Tip: The earthing wire is crucial for preventing electric shocks by directing excess current safely into the ground.


Question 25:

Explain
(i) Fleming’s Left Hand Rule and
(ii) Right Hand Thumb Rule. For which physical quantities are they used for finding their directions?

Correct Answer:
View Solution



- Fleming’s Left Hand Rule: This rule is used to determine the direction of force experienced by a current-carrying conductor in a magnetic field. It states that if the thumb, forefinger, and middle finger of the left hand are stretched perpendicular to each other:

- Forefinger represents the direction of the magnetic field.

- Middle finger represents the direction of current.

- Thumb represents the direction of force (motion).

- Right Hand Thumb Rule: This rule is used to determine the direction of the magnetic field around a current-carrying conductor. If the thumb of the right hand points in the direction of current, then the curled fingers represent the direction of the magnetic field. Quick Tip: Fleming’s Left Hand Rule is used in motors, while the Right Hand Thumb Rule helps in understanding electromagnetism and solenoid fields.


Question 26:

Write the balanced chemical equations for the following reactions:

Correct Answer:
View Solution



(i) Lead nitrate is heated:
\[ 2 \, Pb(NO_3)_2 \xrightarrow{heat} 2 \, PbO + 4 \, NO_2 + O_2 \]

(ii) Ethanoic acid reacts with Sodium carbonate:
\[ CH_3COOH + Na_2CO_3 \rightarrow 2 \, CH_3COONa + CO_2 + H_2O \]

(iii) Reaction of Zinc with Silver nitrate:
\[ Zn + 2 \, AgNO_3 \rightarrow Zn(NO_3)_2 + 2 \, Ag \]

(iv) Reaction of Sodium sulphate solution with Barium chloride solution:
\[ Na_2SO_4 + BaCl_2 \rightarrow BaSO_4 + 2 \, NaCl \]
Quick Tip: Balanced chemical equations are essential for understanding the stoichiometry of reactions.


Question 27:

Write short notes on the following:

Correct Answer:
View Solution



(i) Homologous series: A homologous series is a series of organic compounds with similar chemical properties and a gradual change in physical properties, where each member differs by a -CH₂ group. Examples include alkanes, alkenes, and alkynes.


(ii) Versatile nature of Carbon: Carbon is versatile because it can form long chains, rings, and networks, which are the basis for organic chemistry. Carbon atoms can bond with other elements to form a variety of organic compounds, including hydrocarbons, sugars, and proteins.
Quick Tip: Carbon’s versatility makes it the backbone of organic life.


Question 28:

(a) Write the IUPAC names of the following compounds:

Correct Answer:
View Solution



(i) CH₃COOH is Ethanoic acid.

(ii) CH₃CH₂CH₂Cl is 1-chloropropane.

(iii) CH ≡ CH is Ethyne.
Quick Tip: Always remember to follow IUPAC rules for naming compounds based on structure.


Question 29:

Explain exothermic and endothermic reactions.

Correct Answer:
View Solution



(i) Exothermic reaction: These are reactions in which heat is released to the surroundings. The energy required to break bonds is less than the energy released when new bonds are formed. Examples include combustion and respiration.

(ii) Endothermic reaction: These are reactions in which heat is absorbed from the surroundings. The energy required to break bonds is more than the energy released when new bonds are formed. An example is photosynthesis.
Quick Tip: In exothermic reactions, heat is released, and in endothermic reactions, heat is absorbed.


Question 30:

What is pH value? How is it related to hydrogen ion concentration?

Correct Answer:
View Solution



The pH value is a measure of the hydrogen ion concentration in a solution. It is calculated as the negative logarithm of the hydrogen ion concentration, i.e., \(pH = -\log[H^+]\). The higher the concentration of hydrogen ions, the lower the pH, indicating an acidic solution. Conversely, a lower concentration of hydrogen ions results in a higher pH, indicating a basic solution.

For example, a pH of 7 indicates neutrality (pure water), while values below 7 indicate acidity and above 7 indicate alkalinity.
Quick Tip: A decrease in pH indicates an increase in hydrogen ion concentration, and an increase in pH indicates a decrease in hydrogen ion concentration.


Question 31:

Differentiate between minerals and ores.

Correct Answer:
View Solution



(i) Minerals: A mineral is a naturally occurring inorganic substance with a definite chemical composition and crystal structure. Minerals are the raw materials from which metals can be extracted. For example, \(Haematite (Fe_2O_3)\) is a mineral.

(ii) Ores: An ore is a naturally occurring mineral from which metals can be extracted profitably. It is usually a mixture of a metal compound with other elements. For example, \(Bauxite (Al_2O_3)\) is an ore of aluminum.
Quick Tip: All ores are minerals, but not all minerals are ores.

*The article might have information for the previous academic years, please refer the official website of the exam.

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