
UP Board Class 10 Science Question Paper 2025 (824 CM) with Solution PDF is available for download here. The total marks for the theory paper are 70. Students reported the paper to be moderate.
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What is the unit of power for a lens?
Step 1: Definition of the Power of a Lens
The power of a lens is defined as the inverse of the focal length, and is represented by the formula: \[ P = \frac{1}{f} \]
where \(P\) represents the power in diopters (D), and \(f\) is the focal length in meters.
Step 2: Unit of Power
Since the power is the reciprocal of the focal length, the unit for power is "per meter" (denoted as \(m^{-1}\)). Since the focal length has units of meters, the power of a lens is measured in per metre.
Thus, the correct answer is option (C).
Quick Tip: The power of a lens is measured in diopters (D), and its unit is \textbf{per metre} (\(m^{-1}\)), as it is the reciprocal of the focal length measured in meters.
If a mirror forms a virtual, erect, and magnified image, what type of mirror is it?
Step 1: Understanding the Image Formation
A concave mirror forms a virtual, erect, and magnified image when the object is placed between the focal point and the mirror. In this case, the image appears larger than the object and is virtual and upright.
Step 2: Behavior of Other Mirrors
- A convex mirror always forms a diminished, virtual, and erect image, so it cannot form a magnified image.
- A plane mirror forms a virtual and erect image of the same size as the object.
Step 3: Conclusion
Thus, the only mirror that can form a virtual, erect, and magnified image is the concave mirror.
\[ \boxed{Concave mirror} \] Quick Tip: For a concave mirror, if the object is placed between the focal point and the mirror, the resulting image will be magnified, virtual, and upright.
If the refractive index of glass is 1.5 and the speed of light in air is \(3 \times 10^8\) m/s, what is the speed of light in glass?
Step 1: Formula for Speed of Light in a Medium
The speed of light in any medium is given by: \[ v = \frac{c}{n} \]
where:
- \(v\) is the speed of light in the medium
- \(c\) is the speed of light in a vacuum (which is \(3 \times 10^8\) m/s)
- \(n\) is the refractive index of the medium
Step 2: Calculating the Speed of Light in Glass
Given the refractive index of glass as \(n = 1.5\) and the speed of light in air as \(c = 3 \times 10^8\) m/s, we can find the speed of light in glass using the formula: \[ v = \frac{3 \times 10^8}{1.5} = 2 \times 10^8 \, m/s \]
Step 3: Conclusion
Thus, the speed of light in glass is \(2 \times 10^8\) m/s, which makes option (B) the correct answer.
Quick Tip: The refractive index (\(n\)) is the ratio of the speed of light in a vacuum to the speed of light in a medium. To find the speed of light in a medium, simply divide the speed of light in vacuum by the refractive index.
The blue color of the sky is caused by
Step 1: Understanding Light Scattering
The blue color of the sky is due to a phenomenon known as Rayleigh scattering. In this process, shorter wavelengths of light, such as blue, are scattered more by the gases and particles in Earth's atmosphere compared to longer wavelengths like red.
Step 2: Why the Other Options Are Incorrect
- Reflection and refraction do not account for the blue color of the sky. Reflection affects the surface or object from which the light is reflected, and refraction bends light but does not explain why the sky is blue.
- Dispersion of light refers to the separation of light into different colors, like in a prism, but it doesn't explain the blue appearance of the sky.
Step 3: Conclusion
Therefore, the blue color of the sky is due to the scattering of light.
\[ \boxed{scattering of light \] Quick Tip: Remember, Rayleigh scattering causes the sky to appear blue because shorter wavelengths (blue) scatter more than longer wavelengths (red).
If the electric current passing through a fixed resistor is halved, then the heat produced in it will become
Step 1: Understanding Joule’s Law of Heating
The heat produced due to a current passing through a resistor is given by Joule’s Law: \[ H = I^2 R t \]
where:
- \(H\) is the heat produced
- \(I\) is the current
- \(R\) is the resistance
- \(t\) is the time for which the current flows
Step 2: Halving the Current
If the current \(I\) is halved, the new current becomes \( \frac{I}{2} \). According to Joule's law, the heat produced will now be: \[ H' = \left(\frac{I}{2}\right)^2 R t = \frac{I^2}{4} R t = \frac{1}{4} H \]
Thus, the heat produced is one-fourth of the original heat when the current is halved.
Step 3: Conclusion
Thus, the heat produced when the current is halved becomes one-fourth. The correct answer is option (C).
Quick Tip: Joule’s Law states that the heat produced by a current is directly proportional to the square of the current. Halving the current reduces the heat produced by a factor of four.
The magnitude of magnetic force acting on a current carrying conductor in a uniform magnetic field does not depend on
Step 1: Formula for magnetic force
The magnetic force \( F \) on a current-carrying conductor in a magnetic field is given by the formula: \[ F = BIL \sin \theta \]
where:
- \( B \) is the magnetic field strength,
- \( I \) is the electric current,
- \( L \) is the length of the conductor, and
- \( \theta \) is the angle between the direction of the magnetic field and the direction of current.
Step 2: Analyzing the options
- The force depends on the electric current \( I \), the intensity of the magnetic field \( B \), and the length of the conductor \( L \).
- The force also depends on the angle \( \theta \), which indicates the direction of the electric current relative to the magnetic field. However, the magnitude of the force does not depend on the actual direction of the current, just the angle between the current and the magnetic field.
Step 3: Conclusion
Thus, the magnitude of the magnetic force does not depend on the direction of electric current.
\[ \boxed{direction of electric current} \] Quick Tip: Remember: The magnetic force depends on the current, the magnetic field strength, the length of the conductor, and the angle between them, but not the direction of the current itself.
At the time of short circuit, the electric current in the circuit becomes
Step 1: What is a short circuit?
A short circuit occurs when the current flows along an unintended path, usually one with very low resistance, such as when the live wire directly touches the neutral wire or the ground.
Step 2: Behavior of the current in a short circuit
In a normal circuit, the current is determined by the resistance of the components. However, during a short circuit, the resistance of the path is very low (ideally zero), so according to Ohm’s Law (\( I = \frac{V}{R} \)), the current becomes extremely high as the resistance \(R\) approaches zero.
Step 3: Conclusion
Thus, the current in the circuit during a short circuit becomes very high. The correct answer is option (C).
Quick Tip: In a short circuit, the resistance drops significantly, leading to a massive increase in current. This can cause overheating and damage to the circuit components.
Valency of atom C in C_6H_6 is
Step 1: Structure of C_6H_6
The given compound is C_6\textit{H_6, which is benzene. The structure of benzene consists of six carbon atoms arranged in a hexagonal ring, with alternating single and double bonds between them. Each carbon atom is bonded to one hydrogen atom.
Step 2: Valency of Carbon
Carbon has an atomic number of 6, and its electron configuration is 1s\(^2\) 2s\(^2\) 2p\(^2\). Carbon needs four electrons to complete its octet, which gives it a valency of 4. This allows each carbon atom in the benzene ring to form four bonds—one with a hydrogen atom and three with other carbon atoms.
Step 3: Conclusion
Thus, the valency of carbon (C) in C\(_6\)H\(_6\) (benzene) is 4.
\[ \boxed{4 \] Quick Tip: Remember: Carbon typically has a valency of 4 because it needs four electrons to complete its octet, as seen in its bonding in benzene.
Strong base is
Step 1: Understanding Strong Base
A strong base is a substance that completely dissociates in water to release hydroxide ions (\(OH^-\)). This leads to a high concentration of \(OH^-\) ions in solution.
Step 2: Identifying the Strong Base
Among the options, NaOH (sodium hydroxide) is a well-known strong base because it dissociates completely in water to produce \(OH^-\) ions.
Step 3: Why the Other Options Are Incorrect
- (B) NH\(_4\)OH (ammonium hydroxide) is a weak base because it does not dissociate completely in water.
- (C) Cu(OH)\(_2\) (copper(II) hydroxide) is a weak base and is only slightly soluble in water.
- (D) Al(OH)\(_3\) (aluminum hydroxide) is also a weak base because it is insoluble in water.
Thus, the correct answer is option (A) NaOH.
Quick Tip: Sodium hydroxide (NaOH) is an example of a strong base because it dissociates completely in water, releasing a high concentration of hydroxide ions.
O_2(g) is obtained on heating
Step 1: Decomposition Reaction of Calcium Carbonate
When calcium carbonate (CaCO\(_3\)) is heated, it undergoes a thermal decomposition reaction, producing calcium oxide (CaO) and carbon dioxide (CO\(_2\)). The oxygen gas is produced when the carbon dioxide is removed from the calcium carbonate. The reaction is as follows:
\[ CaCO_3 (s) \xrightarrow{heat} CaO (s) + CO_2 (g) \]
Step 2: Analyzing Other Options
- C\(_6\)H\(_{12}\)O\(_6\) (glucose) does not release oxygen upon heating. It undergoes a process called fermentation or combustion but not oxygen release directly.
- Pb(NO\(_3\))\(_2\) decomposes on heating to give lead(II) oxide (PbO), nitrogen dioxide (NO\(_2\)), and oxygen, but it does not directly give oxygen gas under normal conditions.
- Na\(_2\)CO\(_3\) does not release oxygen upon heating; it is a stable compound that does not decompose to give oxygen.
Step 3: Conclusion
Thus, the correct answer is that oxygen gas is obtained by heating CaCO\(_3\) (calcium carbonate).
\[ \boxed{CaCO_3} \] Quick Tip: Remember: Calcium carbonate decomposes upon heating to release carbon dioxide and calcium oxide. This reaction is important for the industrial production of lime.
Liquid metal at ordinary temperature is
Step 1: Understanding the Concept of Liquid Metal at Ordinary Temperature
At ordinary temperature, most metals are in solid form. However, mercury (Hg) is a metal that is liquid at room temperature (around 25°C), unlike other metals that require higher temperatures to melt.
Step 2: Identifying the Liquid Metal
Mercury is the only metal that is in liquid form at ordinary temperatures. It is unique in this property.
Step 3: Why the Other Options Are Incorrect
- (A) Mg (magnesium) is a solid metal at ordinary temperature.
- (B) Cu (copper) is a solid metal at ordinary temperature.
- (C) Cr (chromium) is a solid metal at ordinary temperature.
Thus, the correct answer is option (D) Hg.
Quick Tip: Mercury (Hg) is the only metal that remains liquid at ordinary temperatures, which is why it is used in thermometers and barometers.
Precipitation reaction is
Step 1: Definition of Precipitation Reaction
A precipitation reaction occurs when two aqueous solutions combine to form an insoluble product, known as the precipitate. This occurs when the product is insoluble in water.
Step 2: Analyzing the options
- In option (A), barium sulfate (BaSO\(_4\)) is formed as a solid precipitate, which is insoluble in water. This makes it a precipitation reaction.
- In option (B), no precipitate is formed; the products are soluble in water, making it not a precipitation reaction.
- In option (C), magnesium sulfate (MgSO\(_4\)) is soluble in water, and thus no precipitate is formed. This is not a precipitation reaction.
- In option (D), sodium oxide (Na\(_2\)O) is formed, which is not a precipitation reaction because it is not insoluble in water.
Step 3: Conclusion
The correct answer is option (A), as it results in the formation of a solid precipitate (BaSO\(_4\)).
\[ \boxed{BaCl_2 (aq) + H_2SO_4 (aq) \(\rightarrow\)BaSO_4 (s) + 2HCl (aq)} \] Quick Tip: Remember: Precipitation reactions result in the formation of an insoluble solid (precipitate) when two soluble compounds react in an aqueous solution.
Molecular formula of butanol-2 is
Step 1: Understanding Butanol-2
Butanol-2, also known as 2-butanol, is an alcohol compound. Alcohols have the general formula C\(_n\)H\(_{2n+1}\)OH. Butanol-2 is a specific isomer of butanol, where the hydroxyl group (OH) is attached to the second carbon of a four-carbon chain.
Step 2: Writing the Molecular Formula
Since butanol-2 is a four-carbon alcohol with a hydroxyl group, its molecular formula is C\(_4\)H\(_{10}\)O. The structure includes 4 carbon atoms, 10 hydrogen atoms, and 1 oxygen atom.
Step 3: Why the Other Options Are Incorrect
- (B) C\(_4\)H\(_8\)O\(_2\): This formula corresponds to butanoic acid, not butanol-2.
- (C) C\(_4\)H\(_{10}\): This formula represents butane, which is an alkane and not an alcohol.
- (D) C\(_4\)H\(_8\): This formula corresponds to 1-butene, an alkene, not an alcohol.
Thus, the correct answer is option (A) C\(_4\)H\(_{10}\)O.
Quick Tip: When identifying alcohols, remember that the molecular formula for alcohols typically ends in -OH (hydroxyl group), and the number of carbon atoms determines the basic formula. For example, butanol-2 is C\(_4\)H\(_{10}\)O.
What are required for photosynthesis?
Step 1: Process of Photosynthesis
Photosynthesis is the process by which plants synthesize food from carbon dioxide and water, using energy from sunlight. This occurs in the chloroplasts of plant cells.
Step 2: Identifying the required components
- The necessary components for photosynthesis are:
- \(\rightarrow\)\(\rightarrow\)Carbon dioxide\(\rightarrow\)\(\rightarrow\) (absorbed from the air),
- \(\rightarrow\)\(\rightarrow\)Water\(\rightarrow\)\(\rightarrow\) (absorbed from the soil),
- \(\rightarrow\)\(\rightarrow\)Chloroplasts\(\rightarrow\)\(\rightarrow\) (where photosynthesis occurs in plant cells),
- \(\rightarrow\)\(\rightarrow\)Sunlight\(\rightarrow\)\(\rightarrow\) (provides the energy required for the process).
Step 3: Analyzing the options
- Option (A) includes oxygen and darkness, neither of which are required for photosynthesis. Oxygen is a byproduct, and sunlight is necessary, not darkness.
- Option (B) includes mitochondria, which are not involved in photosynthesis; they are involved in cellular respiration.
- Option (D) mentions nitrogen, which is not directly involved in photosynthesis.
Step 4: Conclusion
The correct answer is option (C), which lists all the essential components: carbon dioxide, water, chloroplasts, and sunlight.
\[ \boxed{Carbon dioxide, Water, Chloroplast and Sunlight} \] Quick Tip: Remember: Photosynthesis requires carbon dioxide, water, sunlight, and chloroplasts in plant cells to convert light energy into chemical energy.
What is required for the synthesis of thyroxine hormone ?
Step 1: Understanding Thyroxine Hormone
Thyroxine is a hormone produced by the thyroid gland in the human body. It plays an important role in regulating metabolism and growth.
Step 2: Role of Iodine in Thyroxine Synthesis
Iodine is an essential element for the production of thyroxine. The thyroid gland combines iodine with the amino acid tyrosine to form thyroxine. Without sufficient iodine, the thyroid cannot produce enough thyroxine, which leads to various health issues such as goiter.
Step 3: Why the Other Options are Incorrect
- (A) Chlorine: Chlorine does not play a role in the synthesis of thyroxine.
- (C) Fluorine: Fluorine is not involved in thyroxine synthesis either.
- (D) None of these: This option is incorrect because iodine is required for thyroxine synthesis.
Thus, the correct answer is option (B) Iodine.
Quick Tip: Iodine is an essential element for thyroid health. A deficiency in iodine can lead to thyroid-related health problems, including the enlargement of the thyroid gland (goiter).
Mendel crossed long and dwarf plants of pea. The percentage of long and dwarf plants in first filial generation (F\(_1\)) was
Step 1: Mendel's Cross of Pea Plants
Mendel crossed a homozygous long pea plant (dominant, TT) with a homozygous dwarf pea plant (recessive, tt). The F\(_1\) generation consisted of offspring with genotype Tt, where the dominant trait (long plant) expresses itself.
Step 2: Result of the Cross
In Mendel's experiment, all the plants in the F\(_1\) generation were heterozygous (Tt) and exhibited the dominant trait (long plants). The percentage of long plants was 100%. However, in the F\(_2\) generation (produced by self-crossing F\(_1\) plants), the expected ratio of long to dwarf plants was 3:1.
Step 3: Conclusion
Since the F\(_1\) generation consists of 100% long plants (heterozygous Tt), the correct answer is 50% long and 50% dwarf plants in the next generation.
\[ \boxed{50% long and 50% dwarf plants} \] Quick Tip: Remember: In Mendel's pea plant experiments, the F\(_1\) generation from a cross between a homozygous dominant and a homozygous recessive plant shows only the dominant trait. The ratio of traits is observed in F\(_2\).
Which of the following is a biotic component of Ecosystem ?
Step 1: Understanding Ecosystem Components
An ecosystem is made up of both biotic (living) and abiotic (non-living) components. The biotic components include plants, animals, and microorganisms, while abiotic components include factors like temperature, air, minerals, and water.
Step 2: Green Plants as Biotic Component
Green plants are considered biotic components of an ecosystem because they are living organisms. They play a crucial role in photosynthesis, converting solar energy into chemical energy, which supports life in the ecosystem.
Step 3: Why the Other Options are Incorrect
- (B) Temperature: Temperature is an abiotic factor, not a biotic one. It influences the climate and environment of the ecosystem but is not a living component.
- (C) Air: Air, like temperature, is an abiotic component as it consists of gases such as oxygen and carbon dioxide, which are essential for life but are not alive themselves.
- (D) Mineral: Minerals are also abiotic components. They are inorganic substances that are crucial for plant and animal life but are not living organisms.
Thus, the correct answer is option (A) Green plants.
Quick Tip: Biotic components refer to living organisms in an ecosystem, while abiotic components are the non-living elements like air, water, and temperature.
'Guard Cells' are found in
Step 1: Understanding Guard Cells
Guard cells are specialized plant cells that surround stomata (the pores on the surface of leaves and stems). They regulate the opening and closing of the stomata, allowing for the exchange of gases (such as oxygen and carbon dioxide) and controlling water loss through transpiration.
Step 2: Identifying where Guard Cells are found
- Guard cells are found in the stomata, which are tiny pores located on the surface of plant leaves and stems.
- Guard cells are not found in organs like the lung, liver, or heart, as these are animal structures.
Step 3: Conclusion
Thus, guard cells are found in the stomata of plants.
\[ \boxed{stomata \] Quick Tip: Remember: Guard cells are responsible for opening and closing the stomata, controlling gas exchange and water loss in plants.
Ozone gas present in upper surface of atmosphere protects earth from which radiation coming from sun?
Step 1: Understanding Ozone Layer
The ozone layer is located in the upper part of the Earth's atmosphere. It plays a vital role in protecting life on Earth by absorbing and blocking most of the sun's harmful ultraviolet (UV) radiation. UV radiation is a major cause of skin cancer, cataracts, and other health issues.
Step 2: UV Radiation
Ultraviolet radiation is a type of electromagnetic radiation that has a shorter wavelength than visible light but longer than X-rays. UV radiation is harmful to life forms, and the ozone layer filters out the most dangerous types, especially UV-B and UV-C rays.
Step 3: Why the Other Options are Incorrect
- (B) Gamma ray: Gamma rays are high-energy electromagnetic radiation, but they are not significantly absorbed by the ozone layer. Other atmospheric layers and cosmic phenomena mainly interact with gamma rays.
- (C) X-Ray: X-rays also have a high energy but are not the primary type of radiation blocked by the ozone layer. They are absorbed by other atmospheric components.
- (D) Infrared: Infrared radiation is heat radiation and is not harmful like UV rays. The ozone layer does not play a significant role in absorbing infrared radiation.
Thus, the correct answer is option (A) Ultraviolet.
Quick Tip: The ozone layer specifically protects us from ultraviolet radiation, especially the harmful UV-B and UV-C rays.
Which of the following is correctly matched?
Step 1: Understanding Reproduction Types
- \(\rightarrow\)\(\rightarrow\)Fission\(\rightarrow\)\(\rightarrow\) is a type of asexual reproduction in which an organism divides into two or more parts, each growing into a new individual. Amoeba reproduces through binary fission, where the cell divides into two identical cells.
- \(\rightarrow\)\(\rightarrow\)Fragmentation\(\rightarrow\)\(\rightarrow\) is a form of asexual reproduction where the organism breaks into pieces, and each piece grows into a new organism. This method is seen in Bryophytes, like some mosses.
- \(\rightarrow\)\(\rightarrow\)Budding\(\rightarrow\)\(\rightarrow\) is another type of asexual reproduction where a new organism develops from an outgrowth (bud) of the parent. Spirogyra, a type of algae, reproduces through fragmentation, not budding.
- \(\rightarrow\)\(\rightarrow\)Vegetative propagation\(\rightarrow\)\(\rightarrow\) involves the reproduction of plants from non-reproductive parts (like roots, stems, or leaves), not from animals like Hydra. Hydra reproduces by budding, not vegetative propagation.
Step 2: Conclusion
The correct match is Fission — Amoeba, as Amoeba reproduces through binary fission.
\[ \boxed{Fission — Amoeba} \] Quick Tip: Remember: Fission is typical in organisms like Amoeba, while fragmentation, budding, and vegetative propagation are other types of asexual reproduction in different organisms.
(i) Explain with the help of labelled ray diagram, the defect of hypermetropia. How is it corrected by a lens?
Hypermetropia:
Hypermetropia, also known as farsightedness, is a vision defect in which the image of a nearby object is formed behind the retina. This occurs when the eyeball is too short or the eye lens is too weak. In such cases, the person is unable to focus on nearby objects clearly, but distant objects can be seen clearly.
Ray Diagram for Hypermetropia:
In the diagram below, the rays from a near object (O) are converging behind the retina, forming an image beyond the focal point. The defect is corrected by using a converging lens (convex lens), which helps to focus the rays on the retina by converging them before they enter the eye.
Correction:
Hypermetropia is corrected using a convex lens (converging lens) that helps focus the image on the retina. The convex lens converges the incoming rays so that the image is formed directly on the retina, allowing the person to see near objects clearly.
Quick Tip: For hypermetropia, convex lenses are used to converge the light rays before they enter the eye, ensuring that the image is focused on the retina.
(ii) An object at a distance of 16 cm from a spherical mirror forms a virtual image at a distance of 12 cm behind the mirror. Determine the magnification of the image and type of the mirror.
We are given:
- Object distance \( u = -16 \, cm \) (since the object is in front of the mirror)
- Image distance \( v = +12 \, cm \) (since the image is virtual and behind the mirror, the distance is positive)
We can use the mirror formula to calculate the focal length:
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
Substituting the given values:
\[ \frac{1}{f} = \frac{1}{12} - \frac{1}{-16} = \frac{1}{12} + \frac{1}{16} \]
Finding the common denominator:
\[ \frac{1}{f} = \frac{4 + 3}{48} = \frac{7}{48} \]
Thus, the focal length is:
\[ f = \frac{48}{7} \approx 6.86 \, cm \]
Since the focal length is positive, the mirror is a concave mirror (a converging mirror).
Next, the magnification \( m \) can be calculated using the magnification formula:
\[ m = \frac{v}{u} = \frac{12}{-16} = -0.75 \]
So, the magnification is \( -0.75 \), meaning the image is diminished and virtual.
Quick Tip: For virtual images formed by mirrors, the image distance is positive for concave mirrors and negative for convex mirrors. The magnification is negative for real images and positive for virtual images.
(i) Draw a labelled ray diagram to show the formation of a virtual magnified image of an object by a convex lens.
To draw the ray diagram for the formation of a virtual magnified image by a convex lens, follow the steps below:
1. Place the object (represented by an arrow) between the focus (F) and the optical center (O) of the lens.
2. The object emits rays that travel parallel to the principal axis.
3. The parallel ray refracts through the lens and passes through the focal point on the other side.
4. Another ray from the object passes through the optical center and continues in a straight line.
5. The two refracted rays diverge after passing through the lens.
6. These rays appear to come from a point behind the lens, forming a virtual image. The image is upright and magnified.
Ray Diagram:
In the diagram, the object is placed between the focal point and the optical center. The rays diverge after passing through the lens, and the virtual image is formed on the same side as the object.
Quick Tip: In the case of a virtual image formed by a convex lens, the object is always placed between the focus and the lens. The image is magnified, virtual, and upright.
(ii) A convex lens produces an inverted image magnified three times of an object placed at a distance of 15 cm from it. Calculate focal length of the lens.
Given:
- The magnification (\(M\)) is -3 (since the image is inverted).
- The object distance (\(u\)) is -15 cm (negative because the object is on the left of the lens).
We can use the magnification formula and the lens formula to calculate the focal length of the lens.
1. Magnification Formula:
The magnification (\(M\)) is given by the formula:
\[ M = \frac{v}{u} \]
Where:
- \(v\) is the image distance (positive for real images, negative for virtual images),
- \(u\) is the object distance (always negative in lens formulas for objects to the left of the lens).
We know that the magnification is -3, so:
\[ -3 = \frac{v}{-15} \]
Solving for \(v\):
\[ v = 45 \, cm \]
2. Lens Formula:
The lens formula relates the focal length (\(f\)), object distance (\(u\)), and image distance (\(v\)):
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
Substituting the known values of \(v = 45 \, cm\) and \(u = -15 \, cm\):
\[ \frac{1}{f} = \frac{1}{45} - \frac{1}{-15} = \frac{1}{45} + \frac{1}{15} \]
Simplifying:
\[ \frac{1}{f} = \frac{1 + 3}{45} = \frac{4}{45} \]
Therefore,
\[ f = \frac{45}{4} = 11.25 \, cm \]
Conclusion:
The focal length of the convex lens is \(11.25 \, cm\).
Quick Tip: The magnification of a lens is given by the ratio of the image distance to the object distance. The lens formula helps to relate object distance, image distance, and focal length.
In the given electric circuit find the current shown by ammeter A.
Given resistances in the circuit:
\[ R_1 = 5 \, \Omega, \, R_2 = 2 \, \Omega, \, R_3 = 3 \, \Omega, \, R_4 = 1.5 \, \Omega, \, and the voltage V = 8 \, V. \]
To find the current shown by the ammeter, we need to calculate the total resistance in the circuit. The resistors are connected in a combination of series and parallel.
1. First, calculate the equivalent resistance of the resistors \(R_2\) and \(R_3\), which are in parallel:
\[ \frac{1}{R_{eq}} = \frac{1}{R_2} + \frac{1}{R_3} = \frac{1}{2} + \frac{1}{3} = \frac{5}{6}. \]
Therefore,
\[ R_{eq} = \frac{6}{5} = 1.2 \, \Omega. \]
2. Now, the equivalent resistance \(R_{eq} = 1.2 \, \Omega\) is in series with \(R_1 = 5 \, \Omega\) and \(R_4 = 1.5 \, \Omega\). The total resistance \(R_T\) is:
\[ R_T = R_1 + R_{eq} + R_4 = 5 + 1.2 + 1.5 = 7.7 \, \Omega. \]
3. Using Ohm's law, the current \(I\) is given by:
\[ I = \frac{V}{R_T} = \frac{8}{7.7} \approx 1.04 \, A. \]
\[ \boxed{I \approx 1.04 \, A}. \] Quick Tip: For mixed circuits, reduce the parallel resistances first, then add the series resistances. Always use Ohm's law \( I = \frac{V}{R} \) for final current.
Why is tungsten normally used for the construction of filaments of electric bulbs?
Tungsten is widely used for the construction of filaments in electric bulbs due to the following reasons:
1. High Melting Point: Tungsten has a very high melting point of about 3422°C, which allows it to withstand the high temperatures produced when the filament is heated to produce light. This is crucial for the filament’s longevity and efficiency.
2. High Electrical Resistance: Tungsten has high electrical resistance, which causes it to heat up when an electric current flows through it, making it ideal for producing light.
3. Durability: Tungsten filaments have a long life compared to other metals due to their ability to withstand repeated heating and cooling cycles without breaking.
4. Strength and Flexibility: Tungsten is strong and flexible, allowing the filament to be drawn into very thin wires without breaking.
Thus, tungsten is the material of choice because it can handle high temperatures, resists corrosion, and ensures a longer lifespan for the filament.
Quick Tip: Tungsten's high melting point and resistance to thermal expansion make it perfect for light bulb filaments. Remember: high temperature + durability = tungsten.
(i) State any two factors on which the strength of magnetic field produced by a current-carrying solenoid depends.
The strength of the magnetic field produced by a current-carrying solenoid depends on the following factors:
1. Current through the solenoid: The strength of the magnetic field is directly proportional to the amount of current passing through the solenoid. More current produces a stronger magnetic field.
2. Number of turns per unit length: The magnetic field strength increases as the number of turns per unit length of the solenoid increases. A greater number of turns increases the overall magnetic field.
Quick Tip: To increase the magnetic field of a solenoid, either increase the current or increase the number of turns of wire.
(ii) How does an electromagnet differ from a permanent magnet?
An electromagnet differs from a permanent magnet in the following ways:
1. Electromagnet: An electromagnet is a temporary magnet that requires an electric current to produce a magnetic field. When the current is switched off, the magnetic field disappears. The strength of the magnetic field can be controlled by varying the current or the number of turns in the solenoid.
2. Permanent Magnet: A permanent magnet is a material that produces a magnetic field on its own, even in the absence of an electric current. Its magnetic properties do not change unless it is subjected to external forces, such as heat or hammering.
Quick Tip: Electromagnets can be switched on and off, and their strength can be adjusted, while permanent magnets always retain their magnetism.
(iii) State Fleming's left-hand rule.
Fleming's left-hand rule is used to determine the direction of force experienced by a current-carrying conductor placed in a magnetic field. The rule states:
If you stretch the thumb, forefinger, and middle finger of your left hand at right angles to each other, then:
- The thumb points in the direction of the \textit{motion (force) of the conductor.
- The forefinger points in the direction of the \textit{magnetic field.
- The middle finger points in the direction of the \textit{current through the conductor.
This rule helps to determine the direction of motion when a current-carrying conductor is placed in a magnetic field.
Quick Tip: Remember: Left-hand rule applies for motors (motion), while right-hand rule is used for generators (current generation).
(i) Explain the importance of using fuse in a household electric circuit.
The fuse is an essential safety device used in electrical circuits to prevent damage to appliances and wiring. It consists of a thin wire that melts when the current passing through it exceeds a predetermined limit. The primary importance of a fuse in a household electric circuit is:
1. Protection from Overload: Fuses are designed to protect electrical circuits from excessive current flow. When too much current flows due to an overload (like too many appliances being plugged in), the fuse wire melts, breaking the circuit and preventing further damage. Without a fuse, the excessive current could cause the wires to overheat, possibly leading to a fire.
2. Prevention of Appliance Damage: Household appliances are designed to operate within specific current ranges. A fuse helps prevent appliances from damage due to surges of electricity. If a surge or short circuit occurs, the fuse blows, cutting off the power supply and saving the appliance from overheating or burning out.
3. Fire Safety: By melting when the current exceeds safe limits, fuses help avoid fire hazards. Overloaded electrical circuits, if left unchecked, could lead to overheating of wires and could start a fire. A fuse acts as an automatic shut-off mechanism.
4. Economic Benefit: While fuses need to be replaced after they blow, they are cost-effective compared to the potential damage that could be caused by electrical fires or the destruction of expensive appliances.
In essence, fuses are vital for electrical safety, ensuring that any sudden increase in current is quickly addressed, preventing hazards, and maintaining the integrity of the household electrical system. Quick Tip: Always replace blown fuses with the correct rating to maintain the protection level. Never use a higher-rated fuse as it might not protect the circuit effectively.
(ii) What are the usual colours of the following insulations of the electric supply wires?
The insulation colours of electrical supply wires are standardized to ensure that the different wires in an electrical circuit are easily identifiable, and to reduce the risk of electrical accidents. The usual colours are:
1. Live Wire: The live wire is usually coloured Brown or Red. The live wire carries the alternating current (AC) from the power supply to the appliance. The current in the live wire fluctuates between positive and negative voltage.
2. Neutral Wire: The neutral wire is typically coloured Blue. The neutral wire provides the return path for the current back to the power supply. It completes the circuit and allows current to flow through the load (appliance).
3. Earth Wire: The earth wire is coloured Green or Yellow with Green stripes. The earth wire serves as a safety feature by providing a path for electric current to flow into the ground in the event of a fault. If a fault causes the appliance’s metal body to become live, the earth wire directs the current away from the user, preventing electric shock.
These colour codes are used globally to prevent confusion during electrical installations and maintenance. It ensures that anyone working with the electrical system can easily identify the purpose of each wire, minimizing the risk of improper connections and ensuring the safety of both the appliances and the users. Quick Tip: Always follow the correct wire colour codes to avoid accidents. For example, never connect the live wire to the earth wire, as this could lead to a short circuit.
(iii)What is the main purpose of earthing an electrical appliance?
Earthing is a critical safety feature in electrical systems that prevents electric shock and damage to electrical appliances. The main purpose of earthing an electrical appliance is to provide a safe path for the flow of electric current to the ground, in case of faults like short circuits or leakage of current. This is achieved by connecting the metal parts of the appliance (which might become live due to a fault) to the earth through an earth wire. The primary reasons for earthing are:
1. Preventing Electric Shock: If there is a fault in the appliance, such as a live wire touching a metal part of the appliance, the metal part could become live. If someone touches it, they may receive an electric shock. Earthing ensures that the electric current is safely directed to the ground, minimizing the risk of shock.
2. Protecting Appliances: Earthing helps to protect electrical appliances from damage due to electrical faults. Without earthing, electrical surges or faults could cause irreparable damage to the appliance or its components.
3. Fire Prevention: Without earthing, a faulty appliance can accumulate excess charge, leading to the risk of overheating and fires. By directing excess current into the earth, earthing prevents the accumulation of excess electrical energy in the appliance, thereby reducing fire hazards.
4. Maintaining Safety Standards: Earthing is a legal requirement in most countries to ensure the safety of electrical systems in homes and industries. It guarantees that all appliances and electrical systems conform to safety regulations.
By ensuring that faulty electrical currents are safely discharged into the ground, earthing helps in avoiding electrical accidents and ensuring the safety of both people and appliances. Quick Tip: Always check that appliances are properly earthed, especially when they involve metallic parts that could become live. A good earthing system is vital for safety.
(i) In how many steps, is impure metal obtained from concentrated sulphide ore?
Impure metal obtained from concentrated sulphide ore is generally done in two main steps:
1. Roasting:
The concentrated sulphide ore is heated in excess air at high temperatures. During this process, the sulphide ore is converted into the oxide form, and sulfur dioxide gas is released. This is called roasting.
\[ 2ZnS (s) + 3O_2 (g) \(\rightarrow\) 2ZnO (s) + 2SO_2 (g) \]
The resulting zinc oxide is impure.
2. Reduction:
The zinc oxide is then reduced by heating it with carbon (usually coke) at high temperatures to produce pure zinc metal and carbon dioxide gas. This is called reduction.
\[ ZnO (s) + C (s) \(\rightarrow\) Zn (s) + CO_2 (g) \]
Thus, impure metal is obtained from sulphide ore in two steps: roasting and reduction.
Quick Tip: The process of extracting impure metal from its sulphide ore involves roasting to convert sulphide into oxide, followed by reduction to obtain pure metal.
(ii) Explain the purification of impure copper by electrolytic method giving a neat diagram.
Purification of Impure Copper by Electrolytic Method:
The process of purifying impure copper involves electrolytic refining. In this method, copper metal is refined using electrolysis. Here’s how the process works:
1. Electrolyte:
The electrolyte used is a copper sulfate solution (CuSO\(_4\)) containing a small amount of sulfuric acid.
2. Anode and Cathode:
- The impure copper is used as the anode (positive electrode).
- A pure copper strip is used as the cathode (negative electrode).
3. Process:
When an electric current is passed through the electrolyte:
- Copper from the anode dissolves as Cu\(^{2+}\) ions into the solution.
- Cu\(^{2+}\) ions from the electrolyte are reduced to copper metal at the cathode, where pure copper is deposited.
- Impurities, such as silver, gold, and platinum, are left behind as anode mud.
The process is repeated until all the impurities are separated from the copper, and pure copper is deposited at the cathode.
Diagram:
In the diagram above:
- The impure copper (anode) is dissolved in the electrolyte, and pure copper is deposited on the cathode. Impurities are collected at the bottom as anode mud.
Quick Tip: Electrolytic refining of copper helps obtain high-purity copper by dissolving the impure copper at the anode and depositing pure copper at the cathode.
(i) Select oxidising and reducing agents with reason in the following reactions:
In each reaction, we need to identify the species being oxidized (losing electrons) and reduced (gaining electrons). The species that loses electrons is the reducing agent, and the species that gains electrons is the oxidizing agent.
(a) Sn^{++ (aq) \(\rightarrow\) Sn^{+++ (aq):
In this reaction, Sn\(^{++\) loses an electron to form Sn\(^{+++}\). Hence, Sn\(^{++}\) is oxidized. The species that gains the electron is the oxidizing agent.
Reducing agent: Sn^{++ (aq)
Oxidizing agent: Sn^{+++ (aq)
(b) Fe^{+++ (aq) \(\rightarrow\) Fe^{++ (aq):
In this reaction, Fe\(^{+++\) gains an electron to form Fe\(^{++}\), so Fe\(^{+++}\) is reduced. The species that loses the electron is the reducing agent.
Reducing agent: Fe^{+++ (aq)
Oxidizing agent: Fe^{++ (aq)
(c) Na(s) \(\rightarrow\) Na^{+ (aq):
Here, Na (sodium) loses an electron to form Na\(^+\). Therefore, sodium (Na) is oxidized. The species that accepts the electron is the oxidizing agent.
Reducing agent: Na (s)
Oxidizing agent: Na^{+ (aq) Quick Tip: The species that loses electrons (oxidized) is the reducing agent, and the species that gains electrons (reduced) is the oxidizing agent.
(ii) Write the pH value of pure water.
The pH value of pure water is 7. This is because, in pure water, the concentration of hydrogen ions (\(H^+\)) and hydroxide ions (\(OH^-\)) are equal, both being \(10^{-7}\) mol/L at 25°C. The pH is calculated as:
\[ pH = -\log [H^+] \]
Since \([H^+] = [OH^-] = 10^{-7}\) mol/L for pure water, we get:
\[ pH = -\log (10^{-7}) = 7 \]
Thus, the pH value of pure water is 7, which is considered neutral. Quick Tip: A pH value of 7 indicates neutrality, where the concentrations of hydrogen and hydroxide ions are equal in pure water.
(i) Write the applications of the following inorganic compounds:
(a) Plaster of Paris
(b) Bleaching Powder
(c) Sodium Bicarbonate
1. Plaster of Paris (CaSO_4\text{. ½ H_2\text{O):
Plaster of Paris is made by heating gypsum (CaSO₄.2H₂O) to around 150°C. The applications of Plaster of Paris are:
In medicine: Plaster of Paris is used for making orthopedic casts for fractures and bone injuries.
In art: It is used to create molds and sculptures.
In construction: It is used for coating walls and ceilings in the form of plastering.
In fire protection: It is used as a fire-resistant material.
2. Bleaching Powder (Ca(OCl)_2):
Bleaching powder is a chemical compound with bleaching and disinfecting properties. The applications of Bleaching Powder are:
In bleaching: It is used for bleaching cotton and linen in the textile industry.
In water treatment: It is used for disinfecting drinking water by killing bacteria and harmful microorganisms.
In cleaning: It is used to clean and disinfect surfaces in households and industries.
In the preparation of chlorine: Bleaching powder is used to produce chlorine gas when reacted with dilute hydrochloric acid.
3. Sodium Bicarbonate (NaHCO₃):
Sodium bicarbonate, commonly known as baking soda, has many applications:
In baking: It is used as a leavening agent in baking to make dough rise.
In cleaning: It is used as a mild abrasive cleaner and deodorizer for cleaning surfaces and removing stains.
In medicine: It is used as an antacid to treat indigestion and heartburn.
In fire extinguishers: Sodium bicarbonate is used in some types of fire extinguishers to put out fires caused by grease or electrical components. Quick Tip: Plaster of Paris is used for casting and orthopedic applications, bleaching powder for disinfection and bleaching, and sodium bicarbonate for cleaning, baking, and medical use.
(ii) What happens when (write chemical equation only):
Ethanol is heated with \(K_2Cr_2O_7\) and concentrated sulphuric acid?
Ethyl alcohol is heated with glacial acetic acid in presence of conc. \(H_2SO_4\)?
Acetic acid reacts with sodium bicarbonate?
1. Ethanol is heated with K_2Cr_2\text{O_7 and concentrated sulfuric acid:
When ethanol is heated with potassium dichromate (\(K_2Cr_2O_7\)) in the presence of concentrated sulfuric acid (\(H_2SO_4\)), it gets oxidized to acetic acid (\(CH_3COOH\)):
\[ \text{C_2H_5OH + K_2Cr_2O_7 + H_2SO_4 \rightarrow CH_3COOH + Cr}_2(SO_4)_3 + H_2O \]
2. Ethyl alcohol is heated with glacial acetic acid in the presence of conc. \(H_2SO_4\):
When ethyl alcohol (ethanol) is heated with glacial acetic acid in the presence of concentrated sulfuric acid, esterification takes place, forming ethyl acetate (an ester):
\[ C_2H_5OH + CH_3COOH \xrightarrow{conc. H_2SO_4} CH_3COOC_2H_5 + H_2O \]
3. Acetic acid reacts with sodium bicarbonate:
When acetic acid reacts with sodium bicarbonate (\(NaHCO_3\)), carbon dioxide gas (\(CO_2\)) is released, and sodium acetate (\(CH_3COONa\)) is formed:
\[ CH_3COOH + NaHCO_3 \rightarrow CH_3COONa + CO_2 + H_2O \] Quick Tip: In organic reactions: 1. Potassium dichromate and sulfuric acid oxidize ethanol to acetic acid. 2. Glacial acetic acid with ethanol in the presence of sulfuric acid forms ethyl acetate (ester). 3. Acetic acid reacts with sodium bicarbonate to release carbon dioxide.
(i) What happens when (write chemical equation only):
Plaster of Paris reacts with water?
\(NH_3 (g)\) and \(CO_2 (g)\) are passed in the solution of saturated aqueous solution of NaCl?
\(Ca(OH)_2\) (dry) reacts with \(Cl_2\) (g) (dry)?
1. Plaster of Paris reacts with water:
When Plaster of Paris (\(CaSO_4. \frac{1}{2} H_2O\)) reacts with water, it forms gypsum (\(CaSO_4. 2H_2O\)):
\[ CaSO_4. \frac{1}{2} H_2O + H_2O \rightarrow CaSO_4. 2H_2O \]
2. NH_3 (g) and CO_2 (g) \text{ is passed in the solution of saturated aqueous solution of NaCl:
When ammonia (\(NH_3\)) and carbon dioxide (\(CO_2\)) gases are passed through a saturated aqueous solution of sodium chloride (\(NaCl\)), they form ammonium chloride (\(NH_4Cl\)) and sodium bicarbonate (\(NaHCO_3\)):
\[ \text{NH_3 (g) + CO_2 (g) + NaCl (aq) \rightarrow NH_4Cl (aq) + NaHCO_3 (aq) \]
3. Ca(OH)_2 (dry) reacts with Cl_2 (dry):
When dry calcium hydroxide (\(Ca(OH)_2\)) reacts with chlorine gas (\(Cl_2\)), it forms calcium chloride (\(CaCl_2\)) and calcium oxychloride (\(Ca(OCl)_2\)):
\[ \text{Ca(OH)_2 + Cl_2 \rightarrow CaCl_2 + Ca(OCl)_2 + H_2O \] Quick Tip: 1. Plaster of Paris forms gypsum when mixed with water. 2. NH₃ and CO₂ react with NaCl to form ammonium chloride and sodium bicarbonate. 3. Calcium hydroxide reacts with chlorine gas to form calcium chloride and calcium oxychloride.
(ii) Explain the cleansing action of soap.
The cleansing action of soap is due to its amphiphilic nature, meaning it has both hydrophilic (water-attracting) and hydrophobic (water-repelling) ends. When soap is mixed with water, the hydrophilic part of the soap molecule is attracted to water, while the hydrophobic tail is repelled by water but attracted to grease or oil.
- The soap molecules surround grease particles and form structures called micelles. The hydrophobic tails of soap molecules trap the grease in the center, while the hydrophilic heads face outward, allowing the micelles to be suspended in water.
- This makes it easier for the grease to be washed away from the surface.
Thus, soap helps in removing dirt and oil from surfaces by breaking down grease and allowing it to be washed away by water. Quick Tip: Soap molecules have both hydrophilic and hydrophobic parts, which enable them to break down grease and oil, making them easy to wash away with water.
(i) Food chain
(ii) Growth hormone in human.
A food chain represents the sequence of organisms through which energy and nutrients flow in an ecosystem. Each organism in a food chain occupies a specific trophic level, starting with producers (usually plants) and moving up to primary, secondary, and tertiary consumers.
- Producers: These are organisms that produce their own food through photosynthesis, such as plants and algae.
- Primary consumers: Herbivores that feed on producers.
- Secondary consumers: Carnivores that feed on primary consumers.
- Tertiary consumers: Apex predators that feed on secondary consumers.
The energy from the sun is transferred through the food chain, with energy decreasing as it moves up trophic levels. When an organism dies, decomposers break it down, recycling nutrients back into the ecosystem.
(ii) Growth hormone in human.
The growth hormone (GH), also known as somatotropin, is a peptide hormone secreted by the pituitary gland. It plays a critical role in growth, metabolism, and body composition.
- Functions: Growth hormone stimulates the growth of bones and tissues, increases protein synthesis, promotes the breakdown of fats, and helps regulate the body's metabolism.
- Effects on growth: GH stimulates the growth of long bones, particularly during childhood and adolescence. It works by promoting the production of insulin-like growth factor (IGF-1) in the liver, which stimulates growth at the cellular level.
- Disorders: Abnormal levels of GH can lead to disorders such as gigantism (excess GH in childhood) or dwarfism (insufficient GH).
In adulthood, GH helps maintain healthy muscle mass and bone density, while also supporting the body's metabolism.
Quick Tip: In a food chain, energy flows from producers to consumers, with energy being lost at each trophic level.
Differentiate between Autotrophic Nutrition and Heterotrophic Nutrition with examples.
Autotrophic and Heterotrophic nutrition are two distinct modes of nutrition used by organisms. Here’s the difference between the two:
1. Autotrophic Nutrition:
- Organisms that can produce their own food using simple inorganic substances like carbon dioxide and water are called autotrophs.
- This process involves the synthesis of organic compounds (usually glucose) using solar energy through the process of photosynthesis or chemical energy through chemosynthesis.
- Example: Green plants, algae, and some bacteria (e.g., Cyanobacteria).
- These organisms are called \textit{producers because they produce organic compounds that serve as food for other organisms.
2. Heterotrophic Nutrition:
- Organisms that cannot produce their own food and depend on other organisms for food are called heterotrophs.
- Heterotrophs obtain organic substances from other living organisms by ingestion or absorption.
- This type of nutrition includes herbivores, carnivores, omnivores, and decomposers.
- Example: Humans, animals, fungi, and most bacteria.
- These organisms are called \textit{consumers because they consume other organisms for food.
Conclusion:
- Autotrophs can produce their own food, while heterotrophs rely on other organisms for food.
- Both types of organisms play critical roles in ecosystems, where autotrophs serve as the base for food chains, and heterotrophs maintain ecological balance by consuming others.
Quick Tip: Autotrophs use light or chemical energy to make food, while heterotrophs depend on consuming other organisms. Both are essential for sustaining life on Earth.
Write short notes on:
(i) Reflex action
(ii) Lymph
(i) Reflex action
Definition:
Reflex action is an involuntary and automatic response to a stimulus that does not require conscious thought. It is controlled by the spinal cord and occurs quickly to protect the body from injury or harm.
Mechanism:
1. Stimulus: A sudden stimulus (such as touching a hot object) activates sensory receptors in the skin.
2. Sensory Neurons: The sensory neurons carry the signal to the spinal cord.
3. Spinal Cord: The spinal cord processes the information and sends an immediate response.
4. Motor Neurons: The motor neurons carry the response from the spinal cord to the muscles, causing an immediate action (like pulling the hand away).
This entire process occurs without the involvement of the brain, making reflex actions very rapid.
Examples of Reflex Actions:
- The knee-jerk reflex.
- Withdrawal reflex when you touch something hot.
(ii) Lymph
Definition:
Lymph is a colorless fluid that circulates throughout the lymphatic system. It plays a key role in the immune system by transporting white blood cells, proteins, and waste products from tissues to the bloodstream.
Composition:
Lymph contains:
1. Water
2. White blood cells (especially lymphocytes, which help fight infections)
3. Proteins (including antibodies)
4. Waste products (from tissue cells)
5. Fat molecules (absorbed from the digestive system, particularly chyle)
Formation and Circulation:
1. Lymph is formed from interstitial fluid, which is the fluid that bathes the cells of tissues. This fluid is pushed out of blood capillaries and collects in tissue spaces.
2. The excess fluid is absorbed by lymphatic capillaries, forming lymph.
3. The lymph flows through lymph nodes, where it is filtered and cleaned of pathogens. It then moves into larger lymphatic vessels and eventually returns to the bloodstream near the neck.
Functions:
1. Transport of immune cells: Lymph transports lymphocytes to fight infection.
2. Waste removal: It removes waste products from tissues and carries them to the bloodstream for excretion.
3. Absorption of fats: Lymph absorbs fat molecules (chyle) from the digestive system and transports them to the bloodstream.
Conclusion:
Lymph is an important component of the circulatory and immune systems, assisting in nutrient transport, waste removal, and the body's defense against diseases.
Quick Tip: Reflex actions are quick and automatic responses controlled by the spinal cord, essential for quick reactions to avoid injury.
Describe the structure and working method of excretory system of human.
The excretory system in humans is responsible for the removal of waste products and excess substances from the body. It consists of various organs and structures that work together to maintain internal balance (homeostasis) by regulating the composition of body fluids.
Structure:
The primary organs involved in the excretory system are the kidneys, ureters, bladder, and urethra.
1. Kidneys: The kidneys are two bean-shaped organs located on either side of the spine, below the rib cage. They contain millions of microscopic structures called nephrons, which are responsible for filtering blood and removing waste.
- The nephron consists of a renal corpuscle (which includes the glomerulus and Bowman's capsule) and a renal tubule (comprising the proximal convoluted tubule, loop of Henle, distal convoluted tubule, and collecting duct).
- The kidneys filter the blood, removing waste products and excess substances like water, salts, and urea, which are converted into urine.
2. Ureters: Two narrow tubes that carry urine from the kidneys to the bladder. Each ureter is connected to a kidney and empties into the urinary bladder.
3. Bladder: The bladder is a hollow muscular organ that stores urine until it is excreted. It can expand to hold about 400-600 milliliters of urine.
4. Urethra: The urethra is a tube that connects the bladder to the outside of the body. It is responsible for the excretion of urine from the body during urination.
Working Method:
The excretory process involves the filtration of blood, reabsorption of water and essential nutrients, and the elimination of waste. The sequence of steps is as follows:
1. Filtration: Blood from the renal artery enters the kidneys and is filtered in the glomerulus. The pressure forces water, salts, glucose, amino acids, and urea into the Bowman's capsule, forming a filtrate.
2. Reabsorption: The filtrate moves into the renal tubule, where essential substances like glucose, amino acids, and most of the water are reabsorbed into the bloodstream. This process occurs in the proximal convoluted tubule, loop of Henle, and distal convoluted tubule.
3. Secretion: Additional waste products, such as hydrogen ions and potassium, are secreted into the renal tubule from the blood.
4. Excretion: The remaining waste (urine), consisting of urea, excess salts, and water, moves into the collecting duct and is then transported to the bladder through the ureters. Urine is stored in the bladder until it is excreted through the urethra during urination.
The excretory system also helps in regulating the body's fluid balance, electrolyte levels, and blood pressure by adjusting the volume and concentration of urine produced.
Quick Tip: The kidneys play a key role in maintaining homeostasis by filtering blood and regulating water and electrolyte balance, while the bladder stores urine until it is excreted.
Describe the transport in plants and write its importance.
In plants, transport refers to the movement of water, minerals, and food throughout the plant. This process is essential for the plant's survival, growth, and reproduction. The two main types of transport in plants are:
1. Xylem Transport:
Xylem is responsible for the transport of water and minerals from the roots to the leaves and other parts of the plant. This process mainly occurs through transpiration, which is the evaporation of water from the plant's leaves. The loss of water creates a negative pressure that pulls water upward through the xylem.
- Water enters the roots from the soil through osmosis and travels through the root xylem vessels into the plant.
- This transport is unidirectional (from roots to leaves).
2. Phloem Transport:
Phloem is responsible for the transport of food (mainly sugars produced during photosynthesis) from the leaves to other parts of the plant, including the roots. This process is called translocation.
- The movement of food is bidirectional, meaning it can move both up and down in the plant.
- The transport occurs through a pressure gradient in the phloem, where sugars and other organic molecules are loaded into the phloem and moved through the plant by the process of osmosis and active transport.
Importance of Transport in Plants:
The transport system in plants is crucial for several reasons:
1. Water and Nutrient Supply: Xylem transport ensures that water and essential nutrients reach all parts of the plant, enabling metabolic processes like photosynthesis and growth.
2. Food Distribution: Phloem transport ensures that the food produced by leaves during photosynthesis is distributed throughout the plant, supporting growth, storage, and reproduction.
3. Temperature Regulation: Transpiration helps in regulating the plant's temperature by releasing excess heat during the evaporation of water from leaves.
4. Structural Support: The movement of water through the plant helps maintain turgor pressure in the cells, giving the plant structure and support.
Quick Tip: Xylem transports water and minerals, while phloem moves food throughout the plant. Both processes are essential for plant growth, nutrient supply, and reproduction.
*The article might have information for the previous academic years, please refer the official website of the exam.