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Aryaman Sharma

| Updated On - May 29, 2026

The State Common Entrance Test Cell, Maharashtra conducted MHT CET 2026 May 20 Shift 2 PCM from 2 PM to 5 PM in CBT Mode. The MHT CET 2026 today’s question paper included three sections: Physics, Chemistry, and Mathematics with multiple-choice questions carrying a total of 200 marks, as per the MHT CET marking scheme, where 1 mark is awarded for every correct answer and no marks are deducted for wrong answers.

MHT CET 2026 May 20 Shift 2 PCM Question Paper with Solution Pdf is available here for download.

MHT CET 2026 May 20 Shift 2 PCM Question Paper with Solution PDF

MHT CET 2026 May 20 Shift 2 Question Paper Download PDF Check Solutions

Question 1:

Given \( f(x) = x - 1 \), \( h(1) = 4 \), and \( h'(1) = -2 \). If \( g(x) = (f[4(h(x)) + 3])^{2} \), find the value of \( g'(1) \).

  • (A) \(-288\)
  • (B) \(288\)
  • (C) \(-144\)
  • (D) \(144\)

Question 2:

The area in sq. units bounded by the curve \( y = 2\sqrt{1 - x^{2}} \) and the x-axis is :

  • (A) \( \pi \)
  • (B) \( 2\pi \)
  • (C) \( \pi/2 \)
  • (D) \( 4\pi \)

Question 3:

The objective function is \( Z = 3x + 5y \). The difference between the maximum and minimum values of \( Z \) is \( 3a \), subject to constraints: \( x + y \geq 1, 5x + 10y \leq 50, x, y \geq 0 \). Find the value of \( a \).

  • (A) \( 3 \)
  • (B) \( 6 \)
  • (C) \( 9 \)
  • (D) \( 27 \)

Question 4:

The surrounding temperature is \( 20^{\circ}C \). A body cools from \( 100^{\circ}C \) to \( 60^{\circ}C \) in 20 minutes. Find the time taken for the body to cool down to \( 30^{\circ}C \).

  • (A) \( 40 \) minutes
  • (B) \( 50 \) minutes
  • (C) \( 60 \) minutes
  • (D) \( 80 \) minutes

Question 5:

For the parabola \( y^{2} = 16x \), find the distance between the focus and the directrix.

  • (A) \( 2 \)
  • (B) \( 4 \)
  • (C) \( 8 \)
  • (D) \( 16 \)

Question 6:

The lines \( \vec{r} \times \vec{a} = \vec{b} \times \vec{a} \) and \( \vec{r} \times \vec{b} = \vec{a} \times \vec{b} \) intersect at a point, where \( \vec{a} = \hat{i} + \hat{j} \) and \( \vec{b} = \hat{i} - \hat{k} \). Find the point of intersection.

  • (A) \( (2, 1, -1) \)
  • (B) \( (1, 1, -1) \)
  • (C) \( (2, 0, -1) \)
  • (D) \( (1, 0, -1) \)

Question 7:

The statement \( \neg(p \leftrightarrow q) \) is logically equivalent to:

  • (A) \( \neg p \leftrightarrow \neg q \)
  • (B) \( \neg p \rightarrow q \)
  • (C) \( \neg(p \rightarrow \neg q) \)
  • (D) \( p \leftrightarrow \neg q \)

Question 8:

If \( A = \begin{bmatrix} \sec\theta & -\tan\theta \\
-\tan\theta & \sec\theta \end{bmatrix} \) and \( A + adj A = 4I \), then find the value of \( \theta \).

  • (A) \( \pi/6 \)
  • (B) \( \pi/4 \)
  • (C) \( 0 \)
  • (D) \( \pi/3 \)

Question 9:

Let \( f(x) = \sqrt{x^{2} + 1} \), \( g(x) = \frac{x+1}{x^{2}+1} \), \( h(x) = 2x - 3 \). Then, \( f'(h'(g'(x))) = ? \)

  • (A) \( 2/\sqrt{5} \)
  • (B) \( -2/\sqrt{5} \)
  • (C) \( 0 \)
  • (D) \( 1/\sqrt{5} \)

Question 10:

Evaluate: \( \int \frac{x + 1}{x(1 + x e^{x})^{2}} d x \)

  • (A) \( \ln \left| \frac{x e^{x}}{1 + x e^{x}} \right| + \frac{1}{1 + x e^{x}} + C \)
  • (B) \( \ln|x e^{x}| - \ln|1 + x e^{x}| - \frac{1}{1 + x e^{x}} + C \)
  • (C) \( \ln \left| \frac{1 + x e^{x}}{x e^{x}} \right| + \frac{1}{1 + x e^{x}} + C \)
  • (D) \( \frac{1}{1 + x e^{x}} + C \)

MHT CET 2026 2nd Attempt Paper Analysis

*The article might have information for the previous academic years, please refer the official website of the exam.

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