
XAT 2025 Question paper with Answer key and Solution PDF for the exam conducted on January 5, 2025 is available here. The exam is conducted by XLRI Jamshedpur in one shift from 2:00 PM to 5:30 PM. XAT question paper 2025 comprises total 100 MCQs (28 in QADI, 26 in VALR, 21 in DM, and 25 in GK) and 1 essay.
| XAT 2025 Question Paper with Answer Key | Check Solutions |
A and B each purchased plots of land on the Moon from an e-store. A bought a plot in the shape of a square, while B bought a circular plot. Both plots were described by the same diameter. Calculate the ratio of the area of A's land to B's land.
The ratio of the area of A's square plot to B's circular plot is calculated as 4 : π. This represents the comparison of areas derived from the same diameter.
Step 1: Define the common measurement.
Let the diameter common to both plots be d. This measurement determines the side length of A's square plot and the diameter of B's circular plot.
Step 2: Calculate the area of A's square plot.
Since the side length of the square matches the diameter d, the area of A's plot is:
Area of A's plot = d2
Step 3: Calculate the area of B's circular plot.
For B's plot, the diameter d gives its radius as:
r = d / 2
The area of the circular plot is calculated using the formula for the area of a circle:
Area of B's plot = πr2 = π(d/2)2 = πd2/4
Step 4: Calculate the ratio.
To find the ratio of the areas of A's plot to B's plot:
Ratio = Area of A's plot / Area of B's plot = d2 / (πd2/4) = 4 / π
Thus, the ratio of the area of A's plot to B's plot is 4 : π.
A bought a phone from some store and paid 1⁄6 on UPI, 1⁄3 with cash, and the rest of the balance a year later with 10% interest. What was the original price of the phone?
The original price of the phone, denoted as P, can be calculated by summing the amounts paid through UPI, cash, and the balance paid later with interest. Using the total payment as A, the original price is determined as P = (20/21)A.
Step 1: Calculate the initial payment.
A paid 1⁄6P on UPI and 1⁄3P with cash. Adding these amounts:
Initial Payment = 1⁄6P + 1⁄3P = 1⁄2P
Step 2: Determine the remaining balance.
The balance to be paid later is:
Remaining Balance = P − 1⁄2P = 1⁄2P
Step 3: Add interest to the balance.
A paid the remaining balance a year later with 10% interest:
Amount Paid Later = 1⁄2P × (1 + 0.1) = 1⁄2P × 1.1 = 11⁄20P
Step 4: Total the payments.
The total amount paid, A, is the sum of the initial payment and the amount paid later:
Total Payment = 1⁄2P + 11⁄20P = 10⁄20P + 11⁄20P = 21⁄20P
Step 5: Solve for P.
Equate the total payment to A and solve for P:
21⁄20P = A → P = 20⁄21A
Thus, the original price of the phone is P = (20/21)A.
ABCD is a rectangle, with C and D having respective coordinates (-2, 0) and (2, 0). If the area of the rectangle is 24, what would be the best way to describe the equation of line AB (the length)?
The rectangle ABCD has C(-2, 0) and D(2, 0) as points on the base. The distance between C and D determines the length of the base CD:
Length of CD = |x2 - x1| = |2 - (-2)| = 4
Given that the area of the rectangle is 24, the height h can be calculated using the area formula for a rectangle:
Area = Base × Height
24 = 4 × h → h = 24 / 4 = 6
The height of the rectangle represents the vertical distance from the base CD to the opposite side AB. Since CD lies along the x-axis (y = 0), the equation of line AB must be parallel to CD and at a vertical height of h = 6:
y = 6
Step 1: Identify the base of the rectangle.
The base CD lies along the x-axis with endpoints C(-2, 0) and D(2, 0). The length of the base is calculated as:
Length of CD = |x2 - x1| = |2 - (-2)| = 4
Step 2: Use the area to find the height.
The area of the rectangle is given as 24. Using the formula for the area of a rectangle:
Area = Base × Height
Substitute the given values:
24 = 4 × h → h = 24 / 4 = 6
Step 3: Determine the equation of line AB.
Since AB is parallel to CD, it lies at a constant vertical height of h = 6 from the x-axis. Therefore, the equation of line AB is:
y = 6
This line is parallel to the x-axis and represents the opposite side of the rectangle.
A chose an integer X, which is between 2 and 40. A noticed that the integer X is such that when X is divided by any integer between 2 and 40, the remainder is always 1. What is the value of X?
The problem states that X satisfies the condition:
X mod n = 1 for all integers n where 2 ≤ n ≤ 40.
This implies that X − 1 must be divisible by all integers from 2 to 40. Therefore, X − 1 is the least common multiple (LCM) of all integers between 2 and 40.
Step 1: Compute the LCM of integers from 2 to 40.
The LCM of a set of integers is the smallest number that is divisible by each integer in the set. To compute the LCM:
Prime numbers between 2 and 40 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37.
The LCM is calculated as:
LCM = 25 × 33 × 52 × 7 × 11 × 13 × 17 × 19 × 23 × 29 × 31 × 37
Step 2: Determine X.
Let N represent the LCM of integers from 2 to 40. Then:
X − 1 = N → X = N + 1
Step 3: Verify if X is within the range 2 to 40.
The value of N (LCM of integers from 2 to 40) is a very large number, far exceeding 40. Adding 1 to N results in an even larger number. Therefore, no such X exists within the range 2 to 40.
An iron beam made with rare materials has a market price dependent on the square of its diameter. The beam broke into two pieces in the ratio of 4:9. What would be the profit or loss if the broken pieces are sold as they are?
The iron beam, when sold as broken pieces, results in a loss. The loss incurred is proportional to 72/169 of the original price of the beam.
The market price of the beam is proportional to the square of its length (L2). Let the original length of the beam before breaking be L, and let the price per unit squared length be k. The original market price of the beam is:
Original Price = k × L2
Step 1: Lengths of the Broken Pieces
The beam broke into two pieces in the ratio 4:9. Let the lengths of the two pieces be L1 and L2:
L1 = (4 / 13) × L, L2 = (9 / 13) × L
Step 2: Market Price of Broken Pieces
The market price of each piece depends on the square of its length. The prices of the two pieces are:
Price of Piece 1 = k × L12 = k × (4/13 × L)2 = k × (16/169) × L2
Price of Piece 2 = k × L22 = k × (9/13 × L)2 = k × (81/169) × L2
The total price of the broken pieces is:
Total Price of Broken Pieces = k × (16/169) × L2 + k × (81/169) × L2 = k × (97/169) × L2
Step 3: Profit or Loss Calculation
The loss is the difference between the original price and the total price of the broken pieces:
Loss = Original Price − Total Price of Broken Pieces
Loss = k × L2 − k × (97/169) × L2 = k × L2 × (1 − 97/169)
Loss = k × L2 × (72/169)
Final Answer:
The loss incurred is proportional to 72/169 of the original price of the beam.
In an office with 8 employees, the average rating is 30. The top five employees have an average rating of 38, and the bottom three have an average rating of 25. Which of the following is not possible?
The given data is inconsistent because the sum of the ratings for the top five and bottom three employees exceeds the total rating of all employees by 25. Therefore, the described situation is not possible.
Step 1: Total ratings of all employees
The total rating for all 8 employees can be calculated using the average:
Total rating of all employees = Average rating × Number of employees = 30 × 8 = 240
Step 2: Total ratings for top five and bottom three
The total rating of the top five employees is:
Total rating of top five employees = Average rating × Number of employees = 38 × 5 = 190
The total rating of the bottom three employees is:
Total rating of bottom three employees = Average rating × Number of employees = 25 × 3 = 75
Step 3: Consistency check
The sum of the ratings for the top five and bottom three employees is:
Total rating of top five + bottom three = 190 + 75 = 265
However, the total rating for all 8 employees is only 240. This inconsistency shows that the given data cannot coexist. Specifically:
The ratings of the top five and bottom three exceed the total rating by 265 − 240 = 25.
Step 4: Conclusion
The described situation is not possible because the total ratings of the two groups exceed the total rating of all employees.
In an office, there are 4 reviewers named R1, R2, R3, and R4, responsible for reviewing products A, B, C, and D. Ratings are between 1 and 5. Due to a technical glitch, the data for their ratings was deleted, and only the averages were preserved. The data is provided below:
| Reviewer | A | B | C | D | Average |
|---|---|---|---|---|---|
| R1 | ? | 3 | ? | 4 | 4 |
| R2 | 3 | ? | 5 | ? | 4 |
| R3 | ? | 4 | ? | 3 | 4 |
| R4 | ? | 5 | ? | ? | 4.25 |
| Average | 4 | 4 | 4 | 4.25 |
Step 1: Column Averages
Using the column averages, the total ratings for A, B, C, and D are:
Step 2: Row Averages
Using the row averages, the totals for each reviewer are:
Step 3: Solve the Equations
Using substitution and ensuring consistency with the averages, the missing ratings are:
Step 4: Final Table
The final table of ratings is:
| Reviewer | A | B | C | D | Average |
|---|---|---|---|---|---|
| R1 | 4 | 3 | 5 | 4 | 4 |
| R2 | 3 | 3 | 5 | 5 | 4 |
| R3 | 5 | 4 | 4 | 3 | 4 |
| R4 | 3 | 5 | 4 | 5 | 4.25 |
| Average | 4 | 4 | 4 | 4.25 |
A teacher conducted a test every week in an 8-week course, and the scores ranged from 1 to 4. There are two students enrolled, R and S. The following conditions are given:
Let the score in the first test for both R and S be x, where x is a positive integer between 1 and 4. From the second test onwards, let R's score remain y, where y is also a positive integer between 1 and 4. Thus, R's scores for the first three tests are:
x, y, y
The total of R's first three scores is:
x + 2y
Let S's score in the second test be z, and S's scores for the first two tests are:
x, z
The total of S's first two scores is:
x + z
From the condition that R's first three scores equal S's first two scores:
x + 2y = x + z → z = 2y
From the fifth test onwards, S's score matches R's score, which is y. Thus, S's scores for all eight tests are:
x, z, s3, s4, y, y, y, y
where s3 and s4 are unknown scores.
From the geometric progression condition, let a be the first term and r the common ratio of the progression:
Solving these equations gives the values of x, y, z, and r. Assuming x = 2, y = 1, z = 2y = 2, and r = 2, we can verify the conditions:
If R had a score of 4 on the third test, what would S have scored on the third test?
Given that R's scores for the first three tests are x, y, 4, we know from the problem's conditions:
x + 2y = x + z → z = 2y
From the geometric progression condition for S's scores, let a be the first term, r the common ratio, and x = a. S's scores form a progression:
x, x × r, x × r2, ...
From the problem, y = 1 (R maintained the same score y from the second test onwards). If R's third test score is 4, then y must also equal 4. Substituting y = 4:
z = 2y = 2 × 4 = 8
Now, for S's scores:
To determine r, use the progression condition x + z = x(1 + r):
2 + 8 = 2(1 + r) → 10 = 2 + 2r → r = 4
Thus, S's third test score is:
x × r2 = 2 × 42 = 2 × 16 = 32
There is a community located 30 km outside the main city. Mr. S started a grocery business in the community after winning a bid by offering a rent significantly higher than initially proposed by the community council, led by Mr. D. He also agreed to provide an additional 15% of his grocery sales to the council, expecting to benefit from higher sales volumes.
After establishing his business, Mr. S observed that SUV owners in the community purchased goods in bulk from the city weekly and relied on his store only for daily necessities or occasional large purchases like a mixer grinder. Over time, Mr. S noticed that his business was barely breaking even, especially considering the rent would increase every 3 years.
To maximize profits, which option should Mr. S choose?
Analyzing each option:
The best option is: Option 3: Provide goods that are not available but required by the community residents.
By catering to unmet needs, Mr. S can differentiate his business and build a loyal customer base, ensuring steady sales and improved profits.
Due to the expansion of the startup "Rush Em'," which promises grocery delivery to the suburbs within 50 minutes, Mr. S's business begins to decline. What should Mr. S do to counter this challenge?
The best option for Mr. S is to recruit a few employees and provide home delivery to the community residents within 10 minutes. This strategy directly addresses the needs of the local community and differentiates Mr. S's services from "Rush Em'."
Analyzing each option:
Final Recommendation: By choosing Option 2, Mr. S can create a unique value proposition focused on ultrafast delivery for the community, making his services indispensable and difficult for "Rush Em'" to replicate.
As Mr. S's business expands to include selling vegetables, the local vegetable vendors in the community are affected and cease their operations. This impacts some community employees who used to receive free or low-priced vegetables. The community council decides to intervene. What action should they take?
The best option for the community council is to ask Mr. S to provide free or low-priced vegetables to lower-class employees. This ensures support for the affected employees while allowing Mr. S to continue his operations.
Analyzing each option:
Final Recommendation: By choosing Option 2, the community council supports its employees and ensures that Mr. S remains a sustainable business partner in the community.
Scenario: Arya, a graduate from a reputable institute, got a job in an IT company but became bored just after a year of working. Her best friend, S, from the company, joins a top-tier B-school, making Arya tempted to follow the same path. Her friend tells her that doing an MBA will provide a career boost and a higher salary. Arya starts preparing for the same, but preparation alongside her job becomes quite tough, prompting her to ask her friend if she should leave the job.
Arya gets an offer from a top B-school for an agribusiness program. After the initial elation, she starts deliberating since the program does not align with her career path. Meanwhile, she receives an offer for a one-year executive MBA program from a third-tier college, which has stellar placements for its first batch. However, the program is designed for individuals with significant work experience, making Arya, who has only one year of experience, hesitate.
Which of the following factors would make Arya choose the one-year executive program?
The one-year executive program may appeal to Arya if it aligns with her career goals, offers proven placement results, and mitigates concerns about her limited work experience. Additionally, its time efficiency and potential networking opportunities could further influence her decision.
Several factors could influence Arya's decision to choose the one-year executive program over the agribusiness program:
Arya must weigh these factors against the potential risk associated with a less-established program and align her decision with her long-term career aspirations.
After receiving offers from both programs, Arya learns that her IT company is tying up with a top-tier B-school to provide their best 30 employees an opportunity to do a management certification course. However, the selection process, as stated by the founder, will depend on employees' performance or exceptional academic records. Since Arya lacks exceptional academic credentials, she fears she might not be selected for the program.
Which of the following options would alleviate Arya's concern the most?
Arya's concerns can be alleviated the most by focusing on improving her current performance and seeking clarity on the selection criteria, which may prioritize recent contributions over academic credentials.
The following options could alleviate Arya's concerns and increase her confidence about being selected:
By seeking clarity on the selection process and striving to enhance her workplace performance, Arya can address her concerns and position herself as a strong candidate for the program.
*The article might have information for the previous academic years, please refer the official website of the exam.