Zollege is here for to help you!!
Need Counselling
Zollege Team's profile photo

Zollege Team

Content Curator | Updated On - May 16, 2024

JEE Advanced 2019 was conducted on 27 May 2019 in 2 languages. The paper is divided into 3 sections namely Maths, physics, and chemistry. JEE advanced aspirants can go through the previous year's papers and improve their practice.JEE advanced mock tests helps a student to brush up their knowledge. JEE advanced question paper 2019 is available to download for all the codes. Candidates can download the JEE advanced question papers with solutions from the table below:-

Quick links

JEE Advanced 2019 Question Papers

JEE Advanced Test Series Download
JEE Advanced 2019 Paper 1 Click Here
JEE Advanced 2019 Paper 2 Click Here

JEE Advanced Previous Year Question Paper PDF Links

Particulars Link
JEE Advanced 2024 Question Paper PDF Link Click Here
JEE Advanced 2023 Question Paper PDF Link Click Here
JEE Advanced 2022 Question Paper PDF Link Click Here
JEE Advanced 2021 Question Paper PDF Link Click Here
JEE Advanced 2020 Question Paper PDF Link Click Here
JEE Advanced 2018 Question Paper PDF Link Click Here

JEE Advanced 2022 Question paper: FAQ

Ques: Who conducts JEE exams?

Ans: National Testing Agency (NTA) conducts JEE Exams.

Ques: Will JEE 2023 be conducted twice?

Ans: Yes, The NTAwill conduct JEE twice.

Ques: What is the JEE 2023 Exam pattern?

Ans: The JEE exam paper consists of 90 MCQ questions. The paper is divided into 3 sections Maths, chemistry, and physics.

Ques: How many times we can attempt JEE paper?

Ans: you can attemp JEE exam for 3 consecutive years.

Ques:How do I get a copy of the previous year's JEE question paper pdf with solutions?

Ans: JEE advanced previous year paper with answer pdf can be downloaded from this page.

*The article might have information for the previous academic years, please refer the official website of the exam.

Ask your question

Answered Questions

JD

Jyoti Dhama

02 Jul 24
Branch Name Opening Ranks Closing Ranks
B.Tech + M.Tech (Dual Degree) Course (5-year)
Aerospace Engineering 2220 2747
Biotechnology and Biochemical Engineering 3498 3957
Chemical Engineering 2675 2839
Civil Engineering with any of the listed specialization 2963 3186
Computer Science and Engineering 200 344
Electrical Engineering with M.Tech. in any of the listed specialization 1036 1092
Electronics and Electrical Communication Engineering with M.Tech. in any of the listed specialization 722 1015
Mechanical Engineering with M.Tech. in any of the listed specialization 1543 2419
Metallurgical and Materials Engineering 3180 3469
Mining Engineering 3688 3855
...Show More

ZT

Zollege Team

03 May 24

The important formulas for the Mathematics Trigonometry section is as follows:-

Basic Trigonometric Function Formulas

  • sin θ = Opposite Side/Hypotenuse
  • cos θ = Adjacent Side/Hypotenuse
  • tan θ = Opposite Side/Adjacent Side
  • sec θ = Hypotenuse/Adjacent Side
  • cosec θ = Hypotenuse/Opposite Side
  • cot θ = Adjacent Side/Opposite Side

Reciprocal Identities

  • cosec θ = 1/sin θ
  • sec θ = 1/cos θ
  • cot θ = 1/tan θ
  • sin θ = 1/cosec θ
  • cos θ = 1/sec θ
  • tan θ = 1/cot θ

Periodicity Identities (in Radians)

  • sin (π/2 – A) = cos A & cos (π/2 – A) = sin A
  • sin (π/2 + A) = cos A & cos (π/2 + A) = – sin A
  • sin (3π/2 – A)  = – cos A & cos (3π/2 – A)  = – sin A
  • sin (3π/2 + A) = – cos A & cos (3π/2 + A) = sin A
  • sin (π – A) = sin A &  cos (π – A) = – cos A
  • sin (π + A) = – sin A & cos (π + A) = – cos A
  • sin (2π – A) = – sin A & cos (2π – A) = cos A
  • sin (2π + A) = sin A & cos (2π + A) = cos A

Cofunction Identities (in Degrees)

  • sin(90°−x) = cos x
  • cos(90°−x) = sin x
  • tan(90°−x) = cot x
  • cot(90°−x) = tan x
  • sec(90°−x) = cosec x
  • cosec(90°−x) = sec x

Sum & Difference Identities

  • sin(x+y) = sin(x)cos(y)+cos(x)sin(y)
  • cos(x+y) = cos(x)cos(y)–sin(x)sin(y)
  • sin(x–y) = sin(x)cos(y)–cos(x)sin(y)
  • cos(x–y) = cos(x)cos(y) + sin(x)sin(y)

Inverse Trigonometry Formulas

  • sin-1 (–x) = – sin-1 x
  • cos-1 (–x) = π – cos-1 x
  • tan-1 (–x) = – tan-1 x
  • cosec-1 (–x) = – cosec-1 x
  • sec-1 (–x) = π – sec-1 x
  • cot-1 (–x) = π – cot-1 x
...Show More

ZT

Zollege Team

10 Apr 24

Yes, the JEE Main question paper for all shifts is different in order to prevent the leaking of questions. However, the authorities try to maintain the difficulty level across the slots.

...Show More

ZT

Zollege Team

10 Apr 24

JEE Main question paper will be available in online mode after exam concludes on the official website. Moreover, the exam will also be conducted in online mode.

...Show More

ZT

Zollege Team

10 Apr 24

 Hey Ali! As per previous year trends, a score of 150 + in General category may put you in the 96-97 percentile. Although, these are subject to change.

...Show More

Subscribe To Our News Letter

Get Latest Notification Of Colleges, Exams and News

© 2026 Patronum Web Private Limited