
JEE Main 2024 Apr 6 Shift 1 Question Paper with Solution pdf is available for download here. Students found Chemistry easy and Mathematics hard. Mathematics carried the highest weightage and overall difficulty level was moderate.
| JEE Main 2024 Question Paper with Solution Pdf 6 April Shift 1 | Check Solution |

If f(x) =
f(x) = { x³ sin(1/x), x ≠ 0; 0, x = 0 }, then:
Solution: To determine f''(0), we need to compute the first and second derivatives of f(x) and evaluate their limits as x approaches 0.
Since f(x) = x³ sin(1/x) for x ≠ 0 and f(x) = 0 for x = 0:
Thus, f''(0) = 0.
The area of a quadrilateral ABCD with vertices A(3, 1, −1), B(5/3, 7/3, 1/3), C(2, 2, 1), D(10/3, 2/3, −1/3) is:
Solution: The area of the quadrilateral is determined using the cross product of vectors BD and AC to form the parallelogram, followed by halving the result for the triangle's area.
The integral ∫0π/4 (cos²x sin²x) / (cos³x + sin³x)² dx equals:
Solution: The integral is solved using substitution and simplifying trigonometric terms.
The mean and standard deviation of 20 observations are found to be 10 and 2, respectively. On rechecking, an observation was mistakenly taken as 8 instead of 12. The correct standard deviation is:
Solution: Correcting the observation affects both the mean and standard deviation. The standard deviation is recalculated using corrected data.
The function f(x) = (x² + 2x − 15) / (x² − 4x + 9) is:
Solution: The function is analyzed for injectivity (one-one) and surjectivity (onto) based on its behavior.
Let A = {n ∈ [100, 700] ∩ N : n is neither a multiple of 3 nor a multiple of 4}. Then the number of elements in A is:
Solution: The total count is determined using the inclusion-exclusion principle.
Let C be the circle of minimum area touching the parabola y = 6 − x² and the lines y = √3|x|. Then, which one of the following points lies on the circle C?
Solution: The circle's center and radius are determined geometrically to check which point lies on the circle.
For α, β ∈ ℝ and a natural number n, let Ar = | r 1 n² + α
2r 2 n² − β
3r − 2 3 n(3n − 1)/2 |. Then 2A₁₀ − A₅ is:
Solution: The determinant is simplified using matrix operations.
The shortest distance between the lines:
(x − 3)/2 = (y + 15)/−7 = (z − 9)/5 and (x + 1)/2 = (y − 1)/1 = (z − 9)/−3, is:
Solution: The shortest distance is calculated using vector methods.
A company has two plants A and B to manufacture motorcycles. 60% motorcycles are manufactured at plant A and the remaining are manufactured at plant B. 80% of the motorcycles manufactured at plant A are rated of the standard quality, while 90% of the motorcycles manufactured at plant B are rated of the standard quality. A motorcycle picked up randomly from the total production is found to be of the standard quality. If p is the probability that it was manufactured at plant B, then 126p is:
Solution: Bayes' theorem is applied to find the probability p.
Let α, β be the distinct roots of the equation:
x² − (t² − 5t + 6)x + 1 = 0, t ∈ ℝ, and an = αⁿ + βⁿ. Then the minimum value of (a2023 + a2025) / a2024 is:
Solution: Using Newton's theorem, the recurrence relation simplifies the given expression.
Let the relations R1 and R2 on the set X = {1, 2, 3, ..., 20} be given by:
R1 = {(x, y) : 2x − 3y = 2} and R2 = {(x, y) : −5x + 4y = 0}. If M and N be the minimum number of elements required to be added in R1 and R2, respectively, in order to make the relations symmetric, then M + N equals:
Solution: For each relation, calculate missing symmetric pairs.
A variable line of slope m > 0 passing through the point (4, −9) intersects the coordinate axes at the points A and B. The minimum value of the sum of the distances of A and B from the origin is:
Solution: Use the slope-intercept form of the line and the AM-GM inequality.
The interval in which the function f(x) = xx is strictly increasing is:
Solution: Analyze the derivative of f(x) to find intervals of monotonicity.
A circle is inscribed in an equilateral triangle of side 12. If the area and perimeter of any square inscribed in this circle are m and n, respectively, then m + n² is equal to:
Solution: Use geometric relationships to calculate m and n.
The number of triangles whose vertices are at the vertices of a regular octagon but none of whose sides is a side of the octagon is:
Solution: Use combinatorics to calculate the required number of triangles.
Let y = y(x) be the solution of the differential equation:
(1 + x²) dy/dx + y = etan⁻¹(x), y(1) = 0. Then y(0) is:
Solution: Solve using the integrating factor (IF) method.
Let y = y(x) be the solution of the differential equation:
(2x ln x) dy/dx + 2y = 3/x ln x, x > 0, and y(e⁻¹) = 0. Then, y(e) is equal to:
Solution: Solve using the integrating factor method.
Let the area of the region enclosed by the curves y = 3x, 2y = 27 − 3x, and y = 3x − x√x be A. Then 10A is equal to:
Solution: Integrate the regions between the curves to calculate A.
Let f : (−∞, ∞) → ℝ \ {0} be a differentiable function such that:
f'(1) = lima→∞ a²f(1/a). Then:
Solution: Use properties of limits and differentiability.
Let αβγ = 45; α, β, γ ∈ ℝ. If:
x(α, 1, 2) + y(1, β, 2) + z(2, 3, γ) = (0, 0, 0),
for some x, y, z ∈ ℝ, xyz ≠ 0, then 6α + 4β + γ is equal to:
Solution: Solve the system of equations using the determinant condition.
A conic C passes through the point (4, −2) and P(x, y), x ≥ 3, is any point on C. Let the slope of the line touching the conic C only at a single point P be half the slope of the line joining the points P and (3, −5). If the focal distance of the point (7, 1) on C is d, then 12d equals:
Solution: Determine the conic equation and calculate the focal distance.
Let:
Iₖ = ∫01 (1 − x)ᵏ dx, k ∈ ℕ.
Then the value of:
Σk=110 (1/7)(Iₖ − 1) is equal to:
Solution: Use the recurrence relation for Iₖ and simplify the summation.
Let x₁, x₂, x₃, x₄ be the solution of the equation 4x⁴ + 8x³ − 17x² − 12x + 9 = 0 and (4 + x²₁)(4 + x²₂)(4 + x²₃)(4 + x²₄) = 125/16m. Then the value of m is:
Solution: Use the roots of the polynomial to solve for m.
Let L₁, L₂ be the lines passing through the point P(0, 1) and touching the parabola 9x² + 12x + 18y − 14 = 0. Let Q and R be the points on the lines L₁ and L₂ such that the ΔPQR is an isosceles triangle with base QR. If the slopes of the lines QR are m₁ and m₂, then 16(m₁² + m₂²) is equal to:
Solution: Solve for the slopes using the given conditions and calculate the required expression.
If the second, third, and fourth terms in the expansion of (x + y)ⁿ are 135, 30, and 10³, respectively, then 6(n³ + x² + y) is equal to:
Solution: Use the binomial theorem to determine n, x, and y.
Let the first term of a series be T₁ = 6 and its r-th term Tᵣ = 3Tᵣ₋₁ + 6r, r = 2, 3, ..., n. If the sum of the first n terms of this series is 1/5 (n² − 12n + 39)(4.6n − 5.3n + 1), then n is equal to:
Solution: Solve the recurrence relation and equate the given sum to find n.
For n ∈ ℕ, if cot⁻¹ 3 + cot⁻¹ 4 + cot⁻¹ 5 + cot⁻¹ n = π/4, then n is equal to:
Solution: Use the cotangent addition formula to solve for n.
Let P(10, −2, −1) and Q be the foot of the perpendicular drawn from the point R(1, 7, 6) on the line passing through the points (2, −5, 11) and (−6, 7, −5). Then the length of the line segment PQ is equal to:
Solution: Use the parametric equation of the line and perpendicular distance formula.
Let ⃗a = 2i − 3j + 4k, ⃗b = 3i + 4j − 5k, and a vector ⃗c be such that ⃗a × (⃗b + ⃗c) + ⃗b × ⃗c = i + 8j + 13k. If ⃗a ⋅ ⃗c = 13, then (24 − ⃗b ⋅ ⃗c) is equal to:
Solution: Solve the given vector equation to find ⃗b ⋅ ⃗c.
To find the spring constant (k) of a spring experimentally, a student commits a 2% positive error in the measurement of time and a 1% negative error in the measurement of mass. The percentage error in determining the value of k is:
Solution: Using error propagation, the percentage error in determining the spring constant is calculated.
A bullet of mass 50 g is fired with a speed of 100 m/s on a plywood and emerges with 40 m/s. The percentage loss of kinetic energy is:
Solution: Calculate the initial and final kinetic energies and determine the percentage loss.
The ratio of the shortest wavelength of the Balmer series to the shortest wavelength of the Lyman series for hydrogen atom is:
Solution: Use the Rydberg formula for the wavelengths of the Balmer and Lyman series.
To project a body of mass m from Earth’s surface to infinity, the required kinetic energy is (assume the radius of Earth is Re, g = acceleration due to gravity on the surface of Earth):
Solution: Derive the kinetic energy required to escape Earth's gravity.
Electromagnetic waves travel in a medium with speed 1.5 × 10⁸ m/s. The relative permeability of the medium is 2.0. The relative permittivity will be:
Solution: Use the relationship between speed of light, permeability, and permittivity.
Which of the following phenomena is not explained by the wave nature of light?
(A) Reflection
(B) Diffraction
(C) Photoelectric effect
(D) Interference
(E) Polarization
Choose the most appropriate answer from the options below:
Solution: The photoelectric effect cannot be explained by the wave theory and provides evidence for the particle nature of light.
While measuring the diameter of a wire using a screw gauge, the following readings were noted. The main scale reading is 1 mm, and the circular scale reading is equal to 42 divisions. The pitch of the screw gauge is 1 mm, and it has 100 divisions on the circular scale. The diameter of the wire is x/50 mm. The value of x is:
Solution: Calculate the least count and use the readings to find the diameter.
σ is the uniform surface charge density of a thin spherical shell of radius R. The electric field at any point on the surface of the spherical shell is:
Solution: Apply Gauss's law to calculate the electric field.
The value of unknown resistance (x) for which the potential difference between B and D will be zero in the arrangement shown, is:
Solution: Use the Wheatstone bridge condition for balance.
The specific heat at constant pressure of a real gas obeying PV² = RT equation is:
Solution: Use thermodynamic relations to determine the specific heat.
Match List I with List II
List I (Quantity) | List II (Dimension)
Choose the correct answer from the options below:
Solution: By analyzing the dimensions of each quantity, we match the correct pairs based on their units.
Given below are two statements:
Statement I: In an LCR series circuit, current is maximum at resonance.
Statement II: Current in a purely resistive circuit can never be less than that in a series LCR circuit when connected to the same voltage source.
In the light of the above statements, choose the correct option from the given below:
Solution: At resonance, the impedance is minimized, and current is maximized. In a purely resistive circuit, the current is always maximum compared to an LCR circuit.
The correct truth table for the following logic circuit is:
| Option 1 | Option 2 | ||||
|---|---|---|---|---|---|
| A | B | Y | A | B | Y |
| 0 | 0 | 0 | 0 | 0 | 1 |
| 0 | 1 | 0 | 0 | 1 | 1 |
| 1 | 0 | 0 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 | 1 | 1 |
The circuit consists of an AND gate, a NOT gate, and an OR gate. The output Y is determined as follows:
Solution: The truth table for the given circuit can be simplified step by step based on the operations of the AND, NOT, and OR gates.
A sample contains a mixture of helium and oxygen gas. The ratio of root mean square speed of helium and oxygen in the sample is:
Solution: The ratio of root mean square speeds is determined using the square root of the ratio of molar masses.
A light string passing over a smooth light pulley connects two blocks of masses m₁ and m₂ (where m₂ > m₁). If the acceleration of the system is g√2, then the ratio of the masses m₁/m₂ is:
Solution: By using the equation for acceleration and solving for the ratio of m₁ to m₂.
Four particles A, B, C, D of mass m/2, m, 2m, 4m, have the same momentum. The particle with maximum kinetic energy is:
Solution: The particle with the least mass will have the maximum kinetic energy for the same momentum.
A train starting from rest first accelerates uniformly up to a speed of 80 km/h for time t, then it moves with a constant speed for time 3t. The average speed of the train for this duration of the journey will be (in km/h):
Solution: Calculate the total distance and time to determine the average speed.
An element Δl = Δxî is placed at the origin and carries a large current I = 10A. The magnetic field on the y-axis at a distance of 0.5m from the element Δx of 1 cm length is:
Solution: Use the Biot-Savart law to calculate the magnetic field.
A small ball of mass m and density ρ is dropped in a viscous liquid of density ρ₀. After some time, the ball falls with constant velocity. The viscous force on the ball is:
Solution: The viscous force is given by the balance of forces at terminal velocity.
In the photoelectric experiment, energy of 2.48 eV irradiates a photo-sensitive material. The stopping potential was measured to be 0.5 V. The work function of the photo-sensitive material is:
Solution: Use the energy relation for the photoelectric effect.
If the radius of Earth is reduced to three-fourths of its present value without change in its mass, then the value of the duration of the day of Earth will be ____ hours 30 minutes.
Solution: Using conservation of angular momentum, the duration of the day decreases as the radius decreases.
Three infinitely long charged thin sheets are placed as shown in figure. The magnitude of electric field at the point P is xσ/ε₀. The value of x is ______.
Solution: Calculate the net electric field using Gauss's law.
A big drop is formed by coalescing 1000 small droplets of water. The ratio of surface energy of 1000 droplets to that of the big drop is 10x. The value of x is ______.
Solution: Use volume conservation and surface area relationships.
When a DC voltage of 100V is applied to an inductor, a DC current of 5A flows through it. When an AC voltage of 200V peak value is connected to the inductor, its inductive reactance is found to be 20√3 Ω. The power dissipated in the circuit is ____ W.
Solution: Calculate the power dissipated in the AC circuit.
The refractive index of a prism is μ = √3 and the ratio of the angle of minimum deviation to the angle of prism is one. The value of the angle of the prism is ____°.
Solution: Use Snell's law and the condition for minimum deviation to calculate the angle of the prism.
A wire of resistance R and radius r is stretched till its radius becomes r/2. If the new resistance of the stretched wire is xR, then the value of x is ____.
Solution: The resistance increases by a factor of 16 due to the quadrupling of the length when the radius is halved.
The radius of a certain orbit of the hydrogen atom is 8.48 Å. If the energy of the electron in this orbit is E/x, then x = ____ (Given a₀ = 0.529 Å, E = energy of electron in ground state).
Solution: Using the relationship between the radius and energy levels of the hydrogen atom, x is found to be 16.
A circular coil having 200 turns, 2.5 × 10⁻⁴ m² area and carrying 100 μA current is placed in a uniform magnetic field of 1 T. Initially, the magnetic dipole moment (M) was directed along B. Amount of work required to rotate the coil through 90° from its initial orientation such that M becomes perpendicular to B is ____ μJ.
Solution: Work required is given by the change in potential energy of the magnetic dipole.
A particle is doing simple harmonic motion of amplitude 0.06 m and time period 3.14 s. The maximum velocity of the particle is ____ cm/s.
Solution: The maximum velocity in SHM is given by \( v_{\text{max}} = ωA \).
For three vectors A = (−x î − 6 ĵ − 2 k̂), B = (−î + 4 ĵ + 3 k̂) and C = (−8 î − ĵ + 3 k̂), if A · (B × C) = 0, then the value of x is ____.
Solution: Calculate the cross product \( B × C \) and dot it with A.
Functional group present in sulphonic acid is:
Solution: The sulphonic acid group is characterized by the functional group SO3H.
Match List I with List II:
| List I (Molecule / Species) | List II (Property / Shape) |
|---|---|
| A. SO2Cl2 | I. Paramagnetic |
| B. NO | II. Diamagnetic |
| C. NO2- | III. Tetrahedral |
| D. I3- | IV. Linear |
Choose the correct answer from the options given below:
Solution: Match the properties and shapes of the molecules and ions.
Given below are two statements:
Choose the most appropriate answer from the options given below:
Solution: Picric acid is not trinitrotoluene; it is 2,4,6-trinitrophenol.
Which of the following is a metamer of the given compound (X)?
Solution: Metamers have the same molecular formula and functional group but differ in the alkyl groups on either side of the functional group.
DNA molecule contains 4 bases whose structures are shown below. One of the structures is not correct. Identify the incorrect base structure.
Solution: DNA contains adenine, guanine, cytosine, and thymine. The incorrect structure does not match these bases.
Match List I with List II:
| List I (Hybridization) | List II (Orientation in Space) |
|---|---|
| A. sp3 | III. Tetrahedral |
| B. dsp2 | IV. Square planar |
| C. sp3d | I. Trigonal bipyramidal |
| D. sp3d2 | II. Octahedral |
Choose the correct answer from the options below:
Solution: Match the hybridization with its spatial orientation.
Given below are two statements:
Choose the correct answer from the options below:
Solution: Gallium thermometers are designed for high-temperature measurements and are unsuitable for freezing points like 256 K.
Which of the following statements are correct?
Choose the correct answer from the options below:
Solution: Statements A, C, and D are correct as per the properties of the compounds and methods of purification.
Match List I with List II:
| List I (Compound/Species) | List II (Shape/Geometry) |
|---|---|
| A. SF4 | III. See-saw |
| B. BrF3 | IV. Bent T-shape |
| C. BrO3- | II. Pyramidal |
| D. NH4+ | I. Tetrahedral |
Choose the correct answer from the options below:
Solution: Match the compounds with their shapes based on VSEPR theory.
In Reimer-Tiemann reaction, phenol is converted into salicylaldehyde through an intermediate. The structure of the intermediate is:
Solution: The intermediate is the sodium salt of dichlorophenol, formed via the attack of dichlorocarbene (:CCl2) on phenol.
Which of the following material is not a semiconductor?
Solution: Graphite is a good conductor of electricity, not a semiconductor.
Consider the following complexes:
The correct order of A, B, C, and D in terms of wavenumber of light absorbed is:
Solution: The ligand field strength determines the wavenumber of absorption. Strong field ligands like CN- cause higher energy transitions.
Match List I with List II:
| List I (Precipitating reagent and conditions) | List II (Cation) |
|---|---|
| A. NH4Cl + NH4OH | III. Al3+ |
| B. NH4OH + Na2CO3 | IV. Sr2+ |
| C. NH4OH + NH4Cl + H2S gas | II. Pb2+ |
| D. Dilute HCl | I. Mn2+ |
Choose the correct answer from the options below:
Solution: Match the reagents with the cations based on their precipitation reactions.
The electron affinity values are negative for:
Choose the most appropriate answer from the options below:
Solution: Electron affinity is negative for elements that do not readily accept an electron to form a stable anion.
The number of elements from the following that do not belong to lanthanoids is:
Eu, Cm, Er, Tb, Yb, and Lu
Solution: Cm (Curium) is an actinide, while the rest belong to the lanthanoid series.
The density of 'x' M solution ('x' molar) of NaOH is 1.12 g/mL, while in molality, the concentration of the solution is 3m (3 molal). Then x is:
Solution: The relationship between molarity and molality is used with the given density, resulting in x = 3.0 M.
Molarity (M) = (Molality × Density × 1000) / (1000 + (Molality × Molar Mass of Solute)). Substituting values, we find x = 3.0.
Which among the following aldehydes is most reactive towards nucleophilic addition reactions?
Solution: Formaldehyde (HCHO) is the most reactive due to the absence of alkyl groups, leading to reduced steric hindrance and a higher partial positive charge on the carbonyl carbon.
As alkyl groups increase, steric hindrance and electron donation to the carbonyl carbon reduce reactivity towards nucleophiles.
At −20°C and 1 atm pressure, a cylinder is filled with an equal number of H2, I2, and HI molecules for the reaction:
H2(g) + I2(g) ⇌ 2HI(g)
Kp for the process is x × 10−1. x =?
Solution: Using the equilibrium constant expression, Kp = (PHI)² / (PH2 × PI2), and substituting mole fractions, x = 10.
The partial pressures of the gases and the stoichiometry of the reaction allow for the calculation of Kp.
Match List I with List II:
| List I (Compound) | List II (Uses) |
|---|---|
| A. Iodoform | III. Antiseptic |
| B. Carbon tetrachloride | I. Fire extinguisher |
| C. CFC | IV. Refrigerants |
| D. DDT | II. Insecticide |
Choose the correct answer from the options below:
Solution: A-III: Iodoform is an antiseptic; B-I: Carbon tetrachloride is a fire extinguisher; C-IV: CFCs are refrigerants; D-II: DDT is an insecticide.
A conductivity cell with two electrodes (dark side) is half filled with an infinitely dilute aqueous solution of a weak electrolyte. If volume is doubled by adding more water at constant temperature, the molar conductivity of the cell will:
Solution: For infinitely dilute solutions, molar conductivity becomes constant, and further dilution does not change it.
At infinite dilution, ion interactions become negligible, and the limiting molar conductivity remains unaffected by additional water.
Consider the dissociation of the weak acid HX as given below:
HX(aq) ⇌ H+(aq) + X−(aq), Ka = 1.2×10−5
The osmotic pressure of 0.03 M aqueous solution of HX at 300 K is ___ ×10−2 bar (nearest integer).
Given: R = 0.083 L·bar·mol−1·K−1
Solution: The osmotic pressure is calculated using the formula:
Π = iCRT, where i is the van 't Hoff factor considering dissociation.
Considering the degree of dissociation and using the formula for i, the total concentration is adjusted to account for dissociation, leading to an osmotic pressure of approximately 76 × 10−2 bar.
The difference in the ‘spin-only’ magnetic moment values of KMnO4 and the manganese product formed during titration of KMnO4 against oxalic acid in acidic medium is ___ BM (nearest integer).
Solution: In KMnO4, Mn is in the +7 oxidation state (no unpaired electrons, μ = 0 BM). In the reduced product (Mn2+), there are 5 unpaired electrons, giving a spin-only magnetic moment of 6 BM.
The difference is due to the change in the oxidation state of Mn from +7 (KMnO4) to +2 (Mn2+), where the latter has unpaired electrons contributing to its magnetic moment.
Time required for 99.9% completion of a first-order reaction is ___ times the time required for completion of 90% reaction (nearest integer).
Solution: The time for a given percentage completion is proportional to ln(remaining concentration). For 99.9% completion:
t99.9% = (ln(1000) / ln(10)) × t90%, which simplifies to 3 times t90%.
The relationship is derived from the first-order reaction equation: t = (1/k) ln([A]0 / [A]).
Number of molecules from the following which can exhibit hydrogen bonding is ___ (nearest integer):
CH3OH, H2O, C6H6, C6H5NO2, HF, NH3
Solution: Hydrogen bonding is exhibited by CH3OH, H2O, HF, NH3, and C6H5NO2, due to the presence of N-H, O-H, or F-H bonds.
C6H6 (benzene) cannot form hydrogen bonds as it lacks the necessary functional groups for hydrogen bonding.
9.3 g of pure aniline upon diazotization followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/conversion) is _____ g (nearest integer).
Solution: The molecular weight of aniline is 93 g/mol. Given 9.3 g of aniline, this corresponds to 0.1 mol. Each mole of aniline produces 1 mole of dye, and the molecular weight of the dye is 200 g/mol, so:
Mass of dye = 0.1 × 200 = 20 g.
The reaction is a 1:1 stoichiometric conversion, ensuring all aniline converts to dye in 100% yield.
The major product of the following reaction is P:
CH3C≡C-CH3
(i) Na/liq. NH3 → (ii) dil. KMnO4, 273 K → P
The number of oxygen atoms present in product P is _____ (nearest integer).
Solution: The reaction produces a vicinal diol as the final product, with two hydroxyl groups attached to the adjacent carbon atoms, contributing two oxygen atoms.
Na in liquid NH3 reduces the alkyne to a trans-alkene, and KMnO4 hydroxylates the double bond, forming a vicinal diol.
The frequency of the de-Broglie wave of an electron in Bohr’s first orbit of the hydrogen atom is ___ ×1013 Hz (nearest integer).
Given: RH (Rydberg constant) = 2.18×10−18 J, h (Planck’s constant) = 6.6×10−34 J·s.
Solution: The frequency is calculated using the relation ν = E/h, where E is the kinetic energy of the electron in the first orbit.
The energy of the first orbit is derived from E = RH, and substituting values gives ν ≈ 661 ×1013 Hz.
The major products from the following reaction sequence are product A and product B:
B (i) Br2 → (ii) alc. KOH (3 eq.) → A
B (i) Br2 → (ii) Na+/O− (1.0 eq.) → B
The total sum of π electrons in product A and product B are ____ (nearest integer).
Solution: Product A is benzene (6 π electrons), and product B is an alkene (2 π electrons). The total sum is 8 π electrons.
The reaction sequence involves dehydrohalogenation and elimination, leading to aromatic and alkenic structures as products.
Among CrO, Cr2O3, and CrO3, the sum of spin-only magnetic moment values of basic and amphoteric oxides is ___ ×10−2 BM (nearest integer).
Given: Atomic number of Cr is 24.
Solution: CrO (Cr2+) has 4 unpaired electrons, Cr2O3 (Cr3+) has 3 unpaired electrons, and CrO3 (Cr6+) has no unpaired electrons.
The spin-only magnetic moment is μ = √n(n + 2), where n is the number of unpaired electrons. Adding the moments for CrO and Cr2O3 gives 8.77 BM (or 877 ×10−2 BM).
An ideal gas, CV = 5/2 R, is expanded adiabatically against a constant pressure of 1 atm until it doubles in volume. If the initial temperature and pressure is 298 K and 5 atm, respectively, then the final temperature is ____ K (nearest integer).
Solution: Using the adiabatic relation PVγ = constant, where γ = CP/CV, the final temperature is calculated.
For γ = 1.4 (diatomic gas), the relationship T1V1γ−1 = T2V2γ−1 is applied, leading to T2 ≈ 274 K.
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