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JEE Main 2024 Jan 29 Shift 2 Chemistry Question Paper with Solution pdf is available for download here. Students found easy and hard. carried the highest weightage and overall difficulty level was moderate.

JEE Main 2024 Chemistry Question Paper with Answer Key PDF

JEE Main 2024 Question Paper PDF JEE Main 2024 Answer Key PDF
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Question 61:

The ascending acidity order of given H atoms is:

  1. C < D < B < A
  2. A < B < C < D
  3. A < B < D < C
  4. D < C < B < A
Correct Answer: (1) C < D < B < A Solution:

The relative acidities follow from the stability of their conjugate bases in the order C < D < B < A.


Question 62:

Match List I (Bio Polymer) with List II (Monomer):

A. Starch | I. Nucleotide
B. Cellulose | II. α-glucose
C. Nucleic acid | III. β-glucose
D. Protein | IV. α-amino acid

  1. A-II, B-I, C-III, D-IV
  2. A-IV, B-II, C-I, D-III
  3. A-I, B-III, C-IV, D-II
  4. A-II, B-III, C-I, D-IV
Correct Answer: (4) A-II, B-III, C-I, D-IV Solution:

Starch is α-glucose based, Cellulose is β-glucose, Nucleic acids are nucleotides, and Proteins are α-amino acids.


Question 63:

Match List I (Compound) with List II (pKa value):

A. Ethanol   | II. 15.9
B. Phenol   | I. 10.0
C. m-Nitrophenol | IV. 8.3
D. p-Nitrophenol | III. 7.1

  1. A-I, B-II, C-III, D-IV
  2. A-IV, B-I, C-II, D-III
  3. A-III, B-IV, C-I, D-II
  4. A-II, B-I, C-IV, D-III
Correct Answer: (4) A-II, B-I, C-IV, D-III Solution:

Ethanol=15.9, Phenol=10.0, m-Nitrophenol=8.3, p-Nitrophenol=7.1.


Question 64:

Which reaction is correct?

  1. Incorrect reaction
  2. Correct reaction
  3. Partially correct reaction
  4. Not valid reaction
Correct Answer: (2) Correct reaction Solution:

HI adds Markovnikov-style, attaching I to less hydrogenated carbon.


Question 65:

IUPAC name of the compound?

  1. Cyclohex-1-en-2-ol
  2. 1-Hydroxyhex-2-ene
  3. Cyclohex-1-en-3-ol
  4. Cyclohex-2-en-1-ol
Correct Answer: (4) Cyclohex-2-en-1-ol Solution:

The double bond and OH are numbered for lowest locants => 2-en-1-ol.


Question 66:

Correct IUPAC name of K₂MnO₄ is?

  1. Potassium tetraoxopermanganate(VI)
  2. Potassium tetraoxidomanganate(VI)
  3. Dipotassium tetraoxidomanganate(VII)
  4. Potassium tetraoxidomanganese(VI)
Correct Answer: (2) Potassium tetraoxidomanganate (VI) Solution:

Mn is in +6 oxidation => “tetraoxidomanganate(VI).”


Question 67:

Reagent giving red ppt with Ni²⁺ in basic medium?

  1. Sodium nitroprusside
  2. Neutral FeCl₃
  3. Meta-dinitrobenzene
  4. Dimethyl glyoxime
Correct Answer: (4) Dimethyl glyoxime Solution:

DMG + Ni²⁺ => red ppt of Ni(dmg)₂ in basic medium.


Question 68:

Phenol + CHCl₃ + NaOH => acid hydrolysis => product= ? => 2-hydroxybenzaldehyde

  1. Salicylic acid
  2. Benzene-1,2-diol
  3. Benzene-1,3-diol
  4. 2-Hydroxybenzaldehyde
Correct Answer: (4) 2-Hydroxybenzaldehyde Solution:

Reimer-Tiemann reaction forms salicylaldehyde (2-hydroxybenzaldehyde).


Question 69:

Match H spectral series vs region: Lyman/Balmer/Paschen/Pfund => UV/Visible/IR/IR

  1. A-II, B-III, C-I, D-IV
  2. A-I, B-III, C-II, D-IV
  3. A-II, B-IV, C-III, D-I
  4. A-I, B-II, C-III, D-IV
Correct Answer: (3) A-II, B-IV, C-III, D-I Solution:

Lyman=UV, Balmer=visible, Paschen & Pfund=IR.


Question 70:

A brown ppt with Nessler’s reagent => gas=? => NH₃

  1. H₂S
  2. CO₂
  3. NH₃
  4. Cl₂
Correct Answer: (3) NH₃ Solution:

Nessler’s reagent + ammonia => brown precipitate (Millon's base).


Question 71:

The product A in a diazotization + Sandmeyer reaction => chlorobenzene

  1. ...
  2. ...
  3. Chlorobenzene
  4. ...
Correct Answer: (3) Chlorobenzene Solution:

Diazonium salt + Cu₂Cl₂ => chlorobenzene.


Question 72:

Identify reagents for a certain conversion => DIBAL-H, NaOH(alc), Zn/HCl => correct set?

  1. A=LiAlH₄, B=NaOH(aq), C=NH₂NH₂/KOH
  2. A=LiAlH₄, B=NaOH(alc), C=Zn/HCl
  3. A=DIBAL-H, B=NaOH(aq), C=NH₂NH₂/KOH
  4. A=DIBAL-H, B=NaOH(alc), C=Zn/HCl
Correct Answer: (4) Solution:

DIBAL-H => partial ester reduction, NaOH(alc)=> aldol steps, Zn/HCl=> Clemmensen.


Question 73:

Strong reducing agent among Ce=58, Eu=63, Gd=64, Lu=71 => ? => Eu²⁺

  1. Lu³⁺
  2. Gd³⁺
  3. Eu²⁺
  4. Ce⁴⁺
Correct Answer: (3) Eu²⁺ Solution:

Eu²⁺ easily oxidizes to Eu³⁺ => strong reducing agent.


Question 74:

Which chromatography is based on differential adsorption? => Column & TLC => (A,B only)

  1. B only
  2. A only
  3. A & B only
  4. C only
Correct Answer: (3) A & B only Solution:

Column & Thin Layer rely on adsorption, Paper uses partition.


Question 75:

Statements re: Zn, Cd, Hg => correct ones? => B & D only

  1. B, D only
  2. B, C only
  3. A, D only
  4. C, D only
Correct Answer: (1) B, D only Solution:

Zn & Cd no variable O.S., Hg does +1,+2; all are soft metals.


Question 76:

Highest first I.E. among Si, Al, N, C => ? => N

  1. Si
  2. Al
  3. N
  4. C
Correct Answer: (3) N Solution:

N’s half-filled 2p³ => highest I.E.


Question 77:

Alkyl halide => alkyl isocyanide => reagent=? => AgCN

  1. NaCN
  2. NH₄CN
  3. KCN
  4. AgCN
Correct Answer: (4) AgCN Solution:

AgCN + R–X => R–NC due to covalent nature.


Question 78:

Which has geometrical isomerism? => CH₃CH=CHBr

  1. CH₃CH=CHCH₃
  2. CH₂=CBr₂
  3. CH₃CH=CHBr
  4. Cyclohexane
Correct Answer: (3) CH₃CH=CHBr Solution:

Different substituents => restricted rotation => cis/trans forms.


Question 79:

I: F has most negative EGE in group => false. II: O has least negative EGE in group => true => so (I false, II true)

  1. Both true
  2. I true, II false
  3. Both false
  4. I false, II true
Correct Answer: (4) I false, II true Solution:

Cl has more negative EGE than F; O is smallest negative in its group.


Question 80:

Oxygen’s anomaly => small size + high electronegativity

  1. Large size, high EN
  2. Small size, low EN
  3. Small size, high EN
  4. Large size, low EN
Correct Answer: (3) Small size and high electronegativity Solution:

O's unique properties arise from small radius & strong EN.


Question 81:

Total antibonding MOs from 2s,2p in a diatomic => 4

Correct Answer: 4 Solution:

1 antibonding from 2s*, plus 3 from 2p* => total=4.


Question 82:

Brown ring test complex => Fe in +1 state

Correct Answer: +1 Solution:

[Fe(H₂O)₅(NO)]²⁺ => Fe=+1 once charges are tallied.


Question 83:

NH₃ formation => [N₂]=2×10⁻², [H₂]=3×10⁻², [NH₃]=1.5×10⁻² => Kc=? =>417

Correct Answer: 417 Solution:

Kc= [NH₃]² / ([N₂][H₂]³)= (1.5×10⁻²)² /((2×10⁻²)(3×10⁻²)³)=417.


Question 84:

0.8 M H₂SO₄, density=1.06 => molality=? => 815×10⁻³ m

Correct Answer: 815×10⁻³ m Solution:

Mass(1 L)=1060 g, moles acid=0.8 => ~78.4 g => solute in 981.6 g solvent => molality=0.08 mol/kg => 0.815 => 815×10⁻³.


Question 85:

50 mL NaOH neutralizes 50 mL 0.5 M oxalic => mass(NaOH)=4 g

Correct Answer: 4 g Solution:

Eq’s => n(oxalic)= 0.5×0.05=0.025 => n(NaOH)= 2×0.025=0.05 => mass=2g/0.05? => 4g total.


Question 86:

2-formylhex-4-enoic acid => total σ+π bonds=22

Correct Answer: 22 Solution:

Summing 16 sigma, 6 pi => 22 total.


Question 87:

Bromine-82 half-life=36 h => fraction left after 24 h=? =>0.63

Correct Answer: 0.63 Solution:

Using N/N₀= (1/2)^(24/36)= (1/2)^(2/3)=~0.63.


Question 88:

ΔH(vap)(CCl₄)=30.5 kJ/mol => 284 g => heat=? =>56 kJ

Correct Answer: 56 kJ Solution:

Moles=284/154=1.84 => total=1.84×30.5=56 kJ.


Question 89:

AuCl₄⁻ electrolyzed => cathode mass gained 1.314 g => total charge=2 F

Correct Answer: 2 F Solution:

Q= n(e⁻)×F => from mass & eq.wt => 2 F total.


Question 90:

Zero dipole among CH₄,BF₃,H₂O,HF,NH₃,CO₂,SO₂ => total=? =>3

Correct Answer: 3 Solution:

CH₄,BF₃,CO₂ have zero net dipole => total 3.





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