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Sanghamitra Deb

Content Writer | Updated On - Jan 16, 2026

VITEEE Question Papers are the most important study material for effective exam preparation. We at Zollege have provided all VITEEE Previous Year Papers with Solution PDFs here. VITEEE 2020 Biology exam was conducted successfully on Vellore Institute of Technology (VIT).

Students can freely download the VITEEE previous year's question paper PDFs along with their solutions here.We strongly encourage VITEEE aspirants to scan through all the VITEEE Question Paper to know the overall difficulty level,VITEEE Syllabus and understand the changes in VITEEE Exam Pattern over the years.

VITEEE 2020 Biology Question Paper with Solution PDF

VITEEE 2020 Biology Question Paper PDF VITEEE 2020 Biology Solution PDF
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VITEEE 2020 Question Paper with Solution PDF for Biology

Question 1:

Which of the following does not show segmented body plan?

  • (A) Arthropods
  • (B) Annelids
  • (C) Echinoderms
  • (D) Chordates
Correct Answer: (C) Echinoderms
View Solution



Segmentation (metamerism) is a body plan characteristic found in Arthropods (A), Annelids (B), and Chordates (D).


Echinoderms (C), such as starfishes, exhibit pentaradial symmetry in their adult form.


They lack true metameric segmentation.


Therefore, Echinoderms do not show a segmented body plan.
Quick Tip: Metamerism is defined as the serial repetition of body parts. It is highly prominent in segmented worms (Annelids) and insects (Arthropods).


Question 2:

Synapsis occurs between

  • (A) mRNA and ribosomes
  • (B) spindle fibre and centromere
  • (C) two homologous chromosomes
  • (D) two heterologous chromosomes
Correct Answer: (C) two homologous chromosomes
View Solution



Synapsis is the physical pairing of chromosomes during Prophase I of meiosis.


This process involves the precise alignment of two homologous chromosomes.


The paired structure is called a bivalent or tetrad, forming the basis for crossing over.
Quick Tip: Homologous chromosomes are pairs of chromosomes (one inherited from each parent) that contain the same genes in the same order. Synapsis ensures their correct separation in Meiosis I.


Question 3:

Gastrula has a pore which is known as

  • (A) zoospore
  • (B) oospore
  • (C) blastopore
  • (D) gonophore
Correct Answer: (C) blastopore
View Solution



The gastrula stage in embryogenesis follows the blastula stage.


During gastrulation, cell migration creates an internal cavity called the archenteron (primitive gut).


The opening of the archenteron to the exterior of the embryo is called the blastopore.
Quick Tip: The blastopore is the defining feature of the gastrula stage, and its eventual fate determines the developmental lineage (Protostome vs. Deuterostome).


Question 4:

The human genetic disorder caused by the presence of an extra X chromosome is called

  • (A) Klinefelter syndrome
  • (B) Down syndrome
  • (C) Turner syndrome
  • (D) Marfan syndrome
Correct Answer: (A) Klinefelter syndrome
View Solution



Klinefelter syndrome is a sex chromosome aneuploidy characterized by the presence of an extra X chromosome.


The resulting karyotype is typically \(47, XXY\).


Turner syndrome (C) is \(45, XO\) (missing X).


Down syndrome (B) is \(Trisomy 21\) (extra autosome).



\begin{quicktipbox
Sex chromosome aneuploidies like Klinefelter and Turner syndromes occur due to non-disjunction of sex chromosomes during meiosis.
\end{quicktipbox Quick Tip: Sex chromosome aneuploidies like Klinefelter and Turner syndromes occur due to non-disjunction of sex chromosomes during meiosis.


Question 5:

Interferon is a

  • (A) fat
  • (B) protein
  • (C) carbohydrate
  • (D) nucleic acid
Correct Answer: (B) protein
View Solution



Interferons (\(IFNs\)) are signaling molecules classified as cytokines.


Chemically, cytokines are low molecular weight regulatory glycoproteins or proteins.


Interferons are released by virus-infected cells to protect nearby non-infected cells from infection.



\begin{quicktipbox
Interferons are crucial components of the innate immune system, functioning primarily as antiviral agents by inhibiting viral protein synthesis in neighboring cells.
\end{quicktipbox Quick Tip: Interferons are crucial components of the innate immune system, functioning primarily as antiviral agents by inhibiting viral protein synthesis in neighboring cells.


Question 6:

The protein moiety of an enzyme is called as

  • (A) apoenzyme
  • (B) coenzyme
  • (C) cofactor
  • (D) holoenzyme
Correct Answer: (A) apoenzyme
View Solution



Many enzymes require a non-protein component (cofactor) to function.


The complete, active enzyme structure is called the holoenzyme (D).


The protein part of this active enzyme is specifically referred to as the apoenzyme (A).



\begin{quicktipbox
Cofactors and coenzymes are non-protein parts. The apoenzyme is inactive alone; it becomes functional only when bound to the required cofactor, forming the holoenzyme.
\end{quicktipbox Quick Tip: Cofactors and coenzymes are non-protein parts. The apoenzyme is inactive alone; it becomes functional only when bound to the required cofactor, forming the holoenzyme.


Question 7:

Which one of the following is not correct with C4 plants?

  • (A) The primary acceptor of \(CO_2\) is a 3 carbon compound
  • (B) The first stable product is a 4-carbon compound
  • (C) Two different cell types are involved
  • (D) Photorespiration occurs frequently
Correct Answer: (D) Photorespiration occurs frequently
View Solution



In \(C4\) plants, the primary \(CO_2\) acceptor is \(PEP\) (Phosphoenolpyruvate), a 3-carbon compound (A).


The first stable product is Oxaloacetic Acid (\(OAA\)), a 4-carbon compound (B).


The process involves two cell types: mesophyll and bundle sheath cells (C).


The main advantage of the \(C4\) pathway is concentrating \(CO_2\) in bundle sheath cells, thereby minimizing \(RuBisCO\)'s oxygenase activity.


This mechanism significantly reduces or suppresses photorespiration.


Therefore, the statement that photorespiration occurs frequently (D) is incorrect.



\begin{quicktipbox \(C4\) plants show Kranz anatomy and spatial separation of the initial \(CO_2\) fixation (in mesophyll) and the Calvin cycle (in bundle sheath).
\end{quicktipbox Quick Tip: \(C4\) plants show Kranz anatomy and spatial separation of the initial \(CO_2\) fixation (in mesophyll) and the Calvin cycle (in bundle sheath).


Question 8:

Oxygen binding affinity to the haemoglobin is

  • (A) decreased by increase in \(pH\)
  • (B) increased by increase in \(pCO_2\)
  • (C) increased by increase in \(pO_2\)
  • (D) not affected by change in \(pH\), \(pO_2\) and \(pCO_2\)
Correct Answer: (C) increased by increase in \(\text{pO}_2\)
View Solution



The \(O_2\)-\(Hb\) dissociation curve shifts based on metabolic factors.


A high partial pressure of oxygen (\(pO_2\)) maximizes the saturation of \(Hb\), thus increasing its apparent affinity for \(O_2\) (C).


An increase in \(pH\) (alkaline condition) increases affinity (A is incorrect, as it says decreased).


An increase in \(pCO_2\) leads to lower \(pH\) (Bohr effect), decreasing affinity (B is incorrect).


Affinity is highly regulated by these factors (D is incorrect).



\begin{quicktipbox
Factors that shift the \(O_2\)-\(Hb\) curve to the right (decreasing affinity and favoring \(O_2\) release in tissues) are increased \(pCO_2\), increased temperature, increased \(H^+\) (decreased \(pH\)), and increased \(2,3-BPG\).
\end{quicktipbox Quick Tip: Factors that shift the \(O_2\)-\(Hb\) curve to the right (decreasing affinity and favoring \(O_2\) release in tissues) are increased \(pCO_2\), increased temperature, increased \(H^+\) (decreased \(pH\)), and increased \(2,3-BPG\).


Question 9:

Which one of the following techniques cannot be used for the measurement of organic matter in sewage?

  • (A) Chemical oxygen demand (\(COD\))
  • (B) Biochemical oxygen demand (\(BOD\))
  • (C) Total organic carbon (\(TOC\))
  • (D) Membrane filtration technique (\(MFT\))
Correct Answer: (D) Membrane filtration technique (\(\text{MFT}\))
View Solution


\(COD\) (A), \(BOD\) (B), and \(TOC\) (C) are all standard analytical methods used to quantify the amount of organic material or its oxygen demand in wastewater.

\(COD\) measures total oxidizable matter; \(BOD\) measures biodegradable organic matter; \(TOC\) measures total carbon content.


Membrane filtration technique (\(MFT\)) (D) is a procedure used primarily in microbiology.

\(MFT\) is used to isolate and enumerate specific microorganisms, such as indicator bacteria (coliforms), in water samples.


It does not provide a direct measure of the bulk concentration of organic matter.



\begin{quicktipbox
In environmental engineering, \(BOD\) and \(COD\) are primary metrics for pollution load. \(MFT\) focuses on the biological safety and microbial concentration, not organic mass.
\end{quicktipbox Quick Tip: In environmental engineering, \(BOD\) and \(COD\) are primary metrics for pollution load. \(MFT\) focuses on the biological safety and microbial concentration, not organic mass.


Question 10:

Study of population ecology is called

  • (A) autecology
  • (B) demecology
  • (C) demography
  • (D) ethology
Correct Answer: (B) demecology
View Solution



Ecology concerning individuals or single species is autecology (A).


Demecology (B) is the specific branch of ecology dealing with populations, including population size, density, distribution, and growth dynamics.


Demography (C) is the statistical study of human populations, especially concerning size and structure.


Ethology (D) is the scientific study of animal behavior.



\begin{quicktipbox
Ecology is broadly classified into autecology (individual/species level) and synecology (community/ecosystem level). Demecology is the specialized term for population-level study.
\end{quicktipbox Quick Tip: Ecology is broadly classified into autecology (individual/species level) and synecology (community/ecosystem level). Demecology is the specialized term for population-level study.

*The article might have information for the previous academic years, please refer the official website of the exam.

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