
GATE raw marks, normalised marks, score and rank are different measures. Calculate raw marks from the answer key first. The official score formula then uses the paper's qualifying and top-performance benchmarks; multiplying marks by ten is incorrect.
| Question | Correct | Incorrect | Blank |
|---|---|---|---|
| 1-mark MCQ | 1 | -1/3 | 0 |
| 2-mark MCQ | 2 | -2/3 | 0 |
| MSQ | 1 or 2, for the exact correct set | 0; no partial credit | 0 |
| NAT | 1 or 2, for an accepted numerical answer | 0 | 0 |
Add all correct-answer marks, then subtract one-third for each wrong one-mark MCQ and two-thirds for each wrong two-mark MCQ. There is no MCQ-style penalty on MSQ or NAT. An MSQ receives credit only for the exact correct option set.
For example, choosing A and B when A, B and D are correct earns zero, not two-thirds of the marks. Leaving a question blank also earns zero.
| Illustrative answers | Calculation | Raw marks |
|---|---|---|
| 12 correct and 3 wrong one-mark MCQs | 12 - 3/3 | 11 |
| 15 correct and 3 wrong two-mark MCQs | 30 - 6/3 | 28 |
| 4 correct two-mark MSQs | 4 x 2 | 8 |
| 6 correct two-mark NATs | 6 x 2 | 12 |
| Total | 11 + 28 + 8 + 12 | 59 / 100 |
The remaining questions in this example are wrong non-MCQs or blank. 59 raw marks do not mean a GATE score of 590. The counts are illustrative, not a prescribed 2027 question-type distribution.
For a paper held in multiple sessions, GATE normalises marks before calculating the score. Let T be the all-session top-0.1% mean, Q the all-session mean plus standard deviation, Ti the corresponding top mean in session i, and Qi that session's mean plus standard deviation. For raw marks m in session i:
Normalised marks = [(T - Q) / (Ti - Qi)] x (m - Qi) + Q.
The Q values in this normalisation formula are statistical mean-plus-standard-deviation benchmarks. Do not replace them with the capped General qualifying mark used in the score formula. These session statistics cannot be reconstructed from one candidate's response sheet, and normalisation is not a fixed bonus for a reported difficult shift.
The standardised score is calculated as 350 + 550 x (M - Mq) / (Mt - Mq).
| Symbol | Score-formula meaning |
|---|---|
| M | Raw marks for a single-session paper or normalised marks for a multi-session paper |
| Mq | General-category qualifying marks for the paper |
| Mt | Mean marks of the top 0.1% or top 10 candidates, whichever group is larger |
| 350 and 900 | Score values assigned to the qualifying and top-performance benchmarks |
For an illustrative paper with M = 60, Mq = 30 and Mt = 80, the score is 350 + 550 x 30/50 = 680. These are example inputs, not 2027 cutoffs or predicted benchmarks.
The General qualifying mark is the paper's mean plus standard deviation, subject to a minimum of 25 and maximum of 40 marks. OBC-NCL/EWS qualifying marks are 90% of the General threshold; SC/ST/PwD qualifying marks are two-thirds of it. The actual paper-wise values depend on the examination results.
Category qualification is distinct from the scorecard issuance rule. A scorecard can be issued at the SC/ST/PwD threshold even when the candidate has not reached the higher qualifying mark for their own category.
| Measure | Meaning |
|---|---|
| Raw marks | Marks earned from correct responses minus MCQ penalties |
| Normalised marks | Adjusted marks for a multi-session paper using official session statistics |
| GATE score | Standardised score calculated from the paper's qualifying and top-performance benchmarks |
| All India Rank | Position within the applicable paper or optional-subject rank list |
The response sheet and matching answer key support a raw-marks estimate. They do not supply the complete candidate distribution needed for a rank, nor the programme/category/round data behind an admission cutoff.
Yes. MCQ penalties can make net marks negative. Wrong MSQ and NAT answers carry no additional deduction, but they do not cancel MCQ penalties.
No. The score depends on the paper's qualifying and top-performance benchmarks, using normalised marks when applicable. The worked example here gives 680 for 60 marks only because its illustrative benchmarks are 30 and 80.
No. Normalisation uses mean-plus-standard-deviation session and all-session statistics. The General qualifying mark is separately bounded between 25 and 40 and is used in the score formula.
The sheet can support a raw-marks estimate with the correct key. Rank also depends on the other candidates and the applicable paper/rank list. The response sheet does not contain that population data.
No. You must select exactly all correct options. Missing one correct option or adding one incorrect option gives zero.
*The article might have information for the previous academic years, please refer the official website of the exam.
For the UG Engineering courses, candidates need to have 10+2 with 45% for the general category. However, the aggregate percentage will be 40% for SC/ST/OBC. For the PG Engineering courses, candidates need to have graduation with 50% and 45% for the SC/ST/OBC.
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